获取进程列表和隐藏特定应用程序 [英] Getting process list and hiding a specific app

问题描述

如何获取进程列表（在弹出按钮中），然后当用户选择应用程序时，我可以隐藏/杀死/最小化/退出应用程序吗？

How do I get a process list (in a popup button), and then when the user selects the application, can I hide/kill/minimize/quit the application?

推荐答案

- [NSWorkspace runningApplications] 会给你一个 NSArray of NSRunningApplication 表示当前正在运行的进程。我不确定是什么原因导致程序从该列表中排除，但它包括用户已从Finder启动的任何应用程序。它还包括一些你不想混淆的东西（Finder本身和loginwindow过程），以及无面的应用程序。

-[NSWorkspace runningApplications] will give you an NSArray of NSRunningApplication instances representing currently-running processes. I'm not exactly sure what causes a program to be excluded from that list, but it does include any application that the user has launched from the Finder. It also includes a couple of things (the Finder itself, and the loginwindow process) that you don't want to mess with, as well as faceless applications.

您可以使用 filteredArrayWithPredicate：过滤它们;您要保留的对象具有 NSApplicationActivationPolicyRegular 。

You can filter those out using filteredArrayWithPredicate:; the objects you want to keep have an activationPolicy of NSApplicationActivationPolicyRegular.

数组过滤后，您可以使用 bundleIdentifier ， bundleURL 或 localizedName 找到所需的应用程序。然后发送隐藏或终止，你喜欢 NSRunningApplication 实例。

Once the array is filtered, you can search it, using bundleIdentifier, bundleURL, or localizedName to find the app you want. Then send hide or terminate as you like to that NSRunningApplication instance.

Apple有一个示例项目，演示所有这一切，称为 AppList 。

Apple has a sample project that demos all this, called AppList.

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