两个NSDate对象之间的差异 - 结果也是一个NSDate [英] Difference between two NSDate objects -- Result also a NSDate

问题描述

我有两个NSDate对象，我想要两者之间的差异，结果应该是一个NSDate对象。任何想法如何实现这一点？

I have two NSDate objects and I want the difference between the two and the result should again be a NSDate object. Any idea how to achieve this?

在这里，我试图解决一个独特的问题，我必须找出经过的时间，然后本地化经过的时间。我可以本地化它，如果我有在NSDate对象的时间。所以想到创建一个NSDate对象，它的时间组件与两个日期之间的时间间隔相同，这样我可以使用NSDateFormatter进行本地化。

Here, I am trying to address a unique problem where I have to find out the elapsed time and then localize the elapsed time. I can localize it if I have the elapsed time in NSDate object. So thought of creating a NSDate object which has its time component same as time interval between the two dates so that I could use NSDateFormatter to localize it.

推荐答案

NSDate 表示时间上的实例，因此将时间间隔表示为 NSDate 。你想要的是 NSDateComponents ：

NSDate represents an instance in time, so it doesn't make sense to represent an interval of time as an NSDate. What you want is NSDateComponents:

NSDate *dateA;
NSDate *dateB;

NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSDateComponents *components = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDay
                                           fromDate:dateA
                                             toDate:dateB
                                            options:0];

NSLog(@"Difference in date components: %i/%i/%i", components.day, components.month, components.year);

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