NSTimeInterval to HH:mm:ss? [英] NSTimeInterval to HH:mm:ss?

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本文介绍了NSTimeInterval to HH:mm:ss?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果我有一个NSTimeInterval设置为200.0,有没有办法将它转换为00:03:20,我想我可以初始化一个NSDate它,然后使用NSDateFormatter使用HH:mm:ss。我的问题是,有一个快速的方法来做这个或者我必须自己分解号码,并使用 [NSString stringWithFormat:%02d:%02d:%02d,myHour,myMin,mySec] / code> c> 不需要使用 NSDateFormatter

If I have an NSTimeInterval that is set to say 200.0, is there a way to convert that into 00:03:20, I was thinking I could initialise an NSDate with it and then use NSDateFormatter using HH:mm:ss. My question is, is there a quick way to do this or do I have to break up the number myself and use [NSString stringWithFormat: %02d:%02d:%02d, myHour, myMin, mySec]?

推荐答案

或除除和模以外的任何东西。 NSTimeInterval 只是含有秒的双精度。

No need to use NSDateFormatter or anything else than division and modulo. NSTimeInterval is just a double containing seconds.

Swift
$ b

Swift

func stringFromTimeInterval(interval: NSTimeInterval) -> String {
    let interval = Int(interval)
    let seconds = interval % 60
    let minutes = (interval / 60) % 60
    let hours = (interval / 3600)
    return String(format: "%02d:%02d:%02d", hours, minutes, seconds)
}

Objective-C

- (NSString *)stringFromTimeInterval:(NSTimeInterval)interval {
    NSInteger ti = (NSInteger)interval;
    NSInteger seconds = ti % 60;
    NSInteger minutes = (ti / 60) % 60;
    NSInteger hours = (ti / 3600);
    return [NSString stringWithFormat:@"%02ld:%02ld:%02ld", (long)hours, (long)minutes, (long)seconds];
}

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