禁用屏幕上当前视图的用户交互 [英] Disabling user interaction of the current view on screen

问题描述

我的应用程式有许多资料检视和各自的控制器。现在我有一组模型类，其中有业务逻辑。其中一个模型类（NSObject的子类）负责管理安全性。它的目的函数是监听来自web服务器的特定指令，并且如果从服务器到达禁用消息，则禁用UI以用于任何进一步的使用。

My app has many views and their respective controllers. Now I have a set of model classes with business logic in them. One of the model classes(subclass of NSObject) has the responsibility of managing security. It's intended function is to listen for a particular instruction from a web server and if a 'disable' message arrives from server, disable the UI for any further usage.

现在禁用消息可以在应用程序运行期间的任何时刻到达，并且任何视图都可以在屏幕上可见。如何确定哪些视图对用户可见（来自我的模型类），并为其禁用用户互动？

Now the 'disable' message can arrive at any instant during the functioning of the app and any view can be visible on screen. How do I determine which view is visible to the user(from my model class) and disable user interaction for it?

推荐答案

你希望整个应用程序根本不反应？

Maybe you want the whole application to not react at all?

[[UIApplication sharedApplication] beginIgnoringInteractionEvents];

使用 [[UIApplication sharedApplication] endIgnoringInteractionEvents]; 将此
（学分转换为nerith）

use [[UIApplication sharedApplication] endIgnoringInteractionEvents]; to revert this (credits to nerith)

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