从tableViewCell中删除图像编程创建 [英] remove image from tableViewCell created programatically

问题描述

我想移动一个单元格中包含的imageView，它工作，但创建一个新的图像在新的位置保持旧的图像（然后两个显示）。如何删除旧的？使用的代码：

I would like to move an imageView contained on a cell and it works but creating a new image at new position keeping old image (then two are shown). How could I remove old one?? used code:

UIImage *cellImage = [UIImage imageNamed:(@"%@", showIconName)];
UIImageView *imageViewToPutInCell = [[UIImageView alloc] initWithImage:cellImage];

imageViewToPutInCell.frame = CGRectMake(iconPos, 7, cellImage.size.width, cellImage.size.height); 
[cell.contentView addSubview:imageViewToPutInCell];

每次重新加载tableView时，都会创建一个新的重叠图像。

every time that I reload tableView, it creates a new overlapped image.

[cell.contentView removeFromSuperview];使用以前，删除它，但然后新的图像不创建。请帮忙！！ Thanx

[cell.contentView removeFromSuperview]; used before, removes it but then new image is not created. Please help!! Thanx

推荐答案

有几种方法可以做到这一点。没有子类化，你可以在你的imageViewToPutInCell设置标签，然后使用 - [UIView viewWithTag：]来查找和删除视图：

There are a couple of ways to do this. Without subclassing, you could set the tag on your imageViewToPutInCell, then later on, use -[UIView viewWithTag:] to find and remove the view:

int            imageViewTag = 1234;

[[cell.contentView viewWithTag: imageViewTag] removeFromSuperview];
imageViewToPutInCell.tag = imageViewTag;
...

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