检查时间是否落在两次iOS之间 [英] Check whether time falls between two time iOS

问题描述

我有两次让我说8.40am和4.00pm，
我想做的是，想检查当前时间是否落在给定时间之间？

I have two times let say 8.40am and 4.00pm, What i want to do is, want to check whether current time falls between given time or not ?

我试过这段代码，但它不工作:(
你能帮我在哪里我犯错误吗？

I have tried this code snippet but it is not working :( can you please help me out where i am making mistake ?

NSDateComponents *components = [[NSCalendar currentCalendar] components:NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:[NSDate date]];
    NSInteger currHr = [components hour];
    NSInteger currtMin = [components minute];

    NSString startTime = @"21:00";
    NSString endTime = @"07:00";
NSArray *arr=[NSArray arrayWithObjects:startTime,endTime, nil];

    int stHr = [[[[arr objectAtIndex:0] componentsSeparatedByString:@":"] objectAtIndex:0] intValue];
    int stMin = [[[[arr objectAtIndex:0] componentsSeparatedByString:@":"] objectAtIndex:1] intValue];
    int enHr = [[[[arr objectAtIndex:1] componentsSeparatedByString:@":"] objectAtIndex:0] intValue];
    int enMin = [[[[arr objectAtIndex:1] componentsSeparatedByString:@":"] objectAtIndex:1] intValue];

    int formStTime = (stHr*60)+stMin;
    int formEnTime = (enHr*60)+enMin;

    int nowTime = (currHr*60)+currtMin;

    if(nowTime >= formStTime && nowTime <= formEnTime) {
        NSLog(@"Btween......");
    }

提前Thnaks >

编辑：

NSDateComponents *openingTime = [[NSDateComponents alloc] init];
    openingTime.hour = [timeA integerValue]; //8
    openingTime.minute = [timeB integerValue];  //45

    NSDateComponents *closingTime = [[NSDateComponents alloc] init];
    closingTime.hour = [timeC integerValue]; //4
    closingTime.minute = [timeD integerValue];  //43


    NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
        [formatter setDateFormat:@"hh:mm"];

        NSString *nowTimeString = [formatter stringFromDate:[NSDate date]];

    NSDate *now = [formatter dateFromString:nowTimeString]; //3:30

    NSDateComponents *currentTime = [[NSCalendar currentCalendar] components:NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond
                                                                    fromDate:now];

    NSMutableArray *times = [@[openingTime, closingTime, currentTime] mutableCopy];
    [times sortUsingComparator:^NSComparisonResult(NSDateComponents *t1, NSDateComponents *t2) {
        if (t1.hour > t2.hour) {
            return NSOrderedDescending;
        }

        if (t1.hour < t2.hour) {
            return NSOrderedAscending;
        }
        // hour is the same
        if (t1.minute > t2.minute) {
            return NSOrderedDescending;
        }

        if (t1.minute < t2.minute) {
            return NSOrderedAscending;
        }
        // hour and minute are the same
        if (t1.second > t2.second) {
            return NSOrderedDescending;
        }

        if (t1.second < t2.second) {
            return NSOrderedAscending;
        }
        return NSOrderedSame;

    }];

    if ([times indexOfObject:currentTime] == 1) {
        NSLog(@"We are Open!");
    } else {
        NSLog(@"Sorry, we are closed!");
    }

推荐答案

• 
  
• 创建日期组件，以小时，分钟，秒为单位创建日期组件


• 打开，关闭和数组中的当前时间


• 排序数组。如果当前时间在索引1处，则处于开始和结束时间之间


• create date components for opening and closing time.
• create date components with hour, minute, second from date to check
• place opening, closing and current time in an array
• sort array. if current time is at index 1, it lies between opening and closing time

NSDateComponents *openingTime = [[NSDateComponents alloc] init];
openingTime.hour = 8;
openingTime.minute = 40;

NSDateComponents *closingTime = [[NSDateComponents alloc] init];
closingTime.hour = 16;
closingTime.minute = 0;

NSDate *now = [NSDate date];

NSDateComponents *currentTime = [[NSCalendar currentCalendar] components:NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond
                                                                fromDate:now];

NSMutableArray *times = [@[openingTime, closingTime, currentTime] mutableCopy];
[times sortUsingComparator:^NSComparisonResult(NSDateComponents *t1, NSDateComponents *t2) {
    if (t1.hour > t2.hour) {
        return NSOrderedDescending;
    }

    if (t1.hour < t2.hour) {
        return NSOrderedAscending;
    }
    // hour is the same
    if (t1.minute > t2.minute) {
        return NSOrderedDescending;
    }

    if (t1.minute < t2.minute) {
        return NSOrderedAscending;
    }
    // hour and minute are the same
    if (t1.second > t2.second) {
        return NSOrderedDescending;
    }

    if (t1.second < t2.second) {
        return NSOrderedAscending;
    }
    return NSOrderedSame;

}];

if ([times indexOfObject:currentTime] == 1) {
    NSLog(@"We are Open!");
} else {
    NSLog(@"Sorry, we are closed!");
}

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