iphone：我如何获得触摸事件的位置？ [英] iphone: How do I get the location of a touch down event?

问题描述

我有一个空的基于视图的应用程序。我想在屏幕上每次触摸的x，y坐标做一些事情。

 >   - （void）touchesBegan：（NSSet *）touches withEvent：（UIEvent *）event 
  
 
 $ b b 
函数（来自NSRespondrer类）。你可以从你的视图类中重写它。 'touches'变量保存一组'UITouch'实例，您可以查询视图中的位置。
 
I have an empty View-Based app.  I'd like to do something with the x,y coordinates of every touch down on the screen.  How do I do this?
解决方案
Override the 
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
function (from the NSRespondrer class).  You can override it from your view class.  The 'touches' variable hold a set of 'UITouch' instances that you can query for the location in the view.

                        
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