cocos2d计算目的点给定的起点，角度和距离 [英] cocos2d calculate destination point given start point, angle and distance

问题描述

我想的快一个。在Cocos2d和xcode中的第二个问题。

Quick one I think. 2d problem in Cocos2d and xcode.

我有

CGPoint currPoint;
float lineLength;
float angle;

现在，我需要找到lineLength从角度角度的currPoint。

Now, I need to find the point that is lineLength away from currPoint at angle Degrees.

试图搜索，但我发现的答案不是我所寻找的。

Tried to search, but the answers i have found aren't quite what I was looking for. Would appreciate anyone pointing out the (I assume) pretty simple math I have overlooked.

推荐答案

从我的头顶：

CGPoint endPoint;
endPoint.x = sinf(CC_DEGREES_TO_RADIANS(angle)) * lineLength;
endPoint.y = cosf(CC_DEGREES_TO_RADIANS(angle)) * lineLength;
endPoint = ccpAdd(currPoint, endPoint);

不确定向量指向的位置，如果它可以旋转90,180或270度。如果是，只需从角度添加/减去该量。

Not sure where the vector points to, if it may be rotated by 90, 180 or 270 degrees. If so, just add/subtract that amount from angle.

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