Ajax上传不工作codeigniter [英] Ajax upload not working codeigniter
问题描述
我使用codeigniter 3.1。我想使用ajax发布上传数据。
Ajax上传文件不工作。但是当我发布的简单形式没有ajax,它工作正常。
我不知道为什么,但没有错误在控制台。
HTML
<?php echo form_open_multipart(site_url post),['id'=>'uploader'])>
< input type =filename =userfilevalue =>
< input type =submitvalue =Submit/>
<?php echo form_close()?>
JAVASCRIPT
$('#uploader')。submit(function(event){
event.preventDefault ;
$ .ajax({
url:window.location.href +'/ post',
type:POST,
dataType:'json',
data:new FormData(this)
});
});
CONTROLLERS
public function post()
{
$ this-> load-> helper('url');
$ this-> load-> helper('form');
$ this-> load-> library(upload);
$ file = $ this-> common-> nohtml($ this-> input-> post(userfile))
$ this-> upload-> initialize(array(
upload_path=>'upload',
overwrite=> FALSE,
max_filename=> 300,
encrypt_name=> TRUE
));
$ this-> upload-> do_upload('userfile');
$ data = $ this-> upload-> data();
$ image_file = $ data ['file_name'];
}
问题是文件上传使用与其他形式< input>
类型不同的机制。这就是为什么 $ this-> input-> post(userfile)
没有得到你的工作。其他答案建议使用javascript的 FormData
,这也是一样。
HTML / p>
一个用于选择文件并提交的非常简单的表单。请注意从简单按钮更改为< input type =submit...
。这样做使得javascript更容易使用 FormData
对象。
<!DOCTYPE html>
< html>
< head>
< meta http-equiv =Content-Typecontent =text / html; charset = UTF-8/>
< script src =https://code.jquery.com/jquery-2.2.2.js>< / script>
< title>上传测试< / title>
< / head>
< body>
<?= form_open_multipart(upload / post,['id'=>'uploader']); >
< input type =filename =userfile>
< p>
< input type =submitvalue =上传>
< / p>
<?php echo form_close()?>
< div id =message>< / div>
< script>
$('#uploader')。submit(function(event){
event.preventDefault();
$ .ajax({
url:window.location.href + '/ post',
type:POST,
dataType:'json',
data:new FormData(this),
processData:false,
contentType :false,
success:function(data){
console.log(data);
if(data.result === true){
$( ).html(< p> File Upload Succeeded< / p>);
} else {
$(#message)。html ; / p>);
}
$(#message)append(data.message);
}
});
< / script>
< / body>
< / html>
JAVASCRIPT
使用
FormData
捕获字段。
注意,我们不处理按钮点击,而是处理submit事件。$('#uploader')。 submit(function(event){
event.preventDefault();
$ .ajax({
url:window.location.href +'/ post',
type: POST,
dataType:'json',
data:new FormData(this),
processData:false,
contentType:false,
success:function ){
//取消注释在javascript控制台中记录返回数据的下一行
// console.log(data);
if(data.result === true){
$(#message)。html(< p> File Upload Succeeded< / p>);
} else {
$(#message)。html < p>文件上传失败!< / p>);
}
$(#message)append(data.message);
}
} );
});
CONTROLLER
我添加了一些代码报告结果到ajax,并将其显示在上传页面。
extends CI_Controller
{
public function __construct()
{
parent :: __ construct();
$ this-> load-> helper(['form','url']);
}
public function index()
{
$ this-> load-> view('upload_v');
}
public function post()
{
$ this-> load-> library(upload);
$ this-> upload-> initialize(array(
upload_path=>'./uploads/',
'allowed_types'=>'gif | jpg | png | doc | txt',
overwrite=> FALSE,
max_filename=> 300,
encrypt_name=> TRUE,
)
$ successful = $ this-> upload-> do_upload('userfile');
if($ successful)
{
$ data = $ this-> upload-> data();
$ image_file = $ data ['file_name'];
$ msg =< p>文件:{$ image_file}< / p>;
$ this-> data_models-> update($ this-> data-> INFO,array(image=> $ image_file));
} else {
$ msg = $ this-> upload-> display_errors();
}
echo json_encode(['result'=> $ successful,'message'=> $ msg]);
}
}
这将上传您的文件。你的工作可能没有完成,因为我怀疑你没有保存你需要的所有文件信息db。这,我怀疑你会对上传的文件的名称感到惊讶。
我建议你学习PHP 处理文件上传,并在此处查看与文件上传相关的一些类似的代码信息相关问题。
I am using codeigniter 3.1 . I want to post upload data using ajax.
Ajax upload file not working. But when i post the simple form without ajax, it working fine.
I don't know why but no error in console.
HTML
<?php echo form_open_multipart(site_url("upload/post"), ['id' => 'uploader']) ?> <input type="file" name="userfile" value=""> <input type="submit" value="Submit" /> <?php echo form_close() ?>
JAVASCRIPT
$('#uploader').submit(function (event) { event.preventDefault(); $.ajax({ url: window.location.href + '/post', type: "POST", dataType: 'json', data: new FormData(this) }); });
CONTROLLERS
public function post() { $this->load->helper('url'); $this->load->helper('form'); $this->load->library("upload"); $file = $this->common->nohtml($this->input->post("userfile")); $this->upload->initialize(array( "upload_path" => 'upload', "overwrite" => FALSE, "max_filename" => 300, "encrypt_name" => TRUE )); $this->upload->do_upload('userfile'); $data = $this->upload->data(); $image_file = $data['file_name']; }
解决方案One of the issues is that file uploading uses a different mechanism than the other form
<input>
types. That is why$this->input->post("userfile")
isn't getting the job done for you. Other answers have suggested using javascript'sFormData
and this one does too.HTML
A very simple form for picking a file and submitting it. Note the change from a simple button to
<input type="submit"...
. Doing so makes it a lot easier for the javascript to use theFormData
object.<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <script src="https://code.jquery.com/jquery-2.2.2.js"></script> <title>Upload Test</title> </head> <body> <?= form_open_multipart("upload/post", ['id' => 'uploader']); ?> <input type="file" name="userfile"> <p> <input type="submit" value="Upload"> </p> <?php echo form_close() ?> <div id="message"></div> <script> $('#uploader').submit(function (event) { event.preventDefault(); $.ajax({ url: window.location.href + '/post', type: "POST", dataType: 'json', data: new FormData(this), processData: false, contentType: false, success: function (data) { console.log(data); if (data.result === true) { $("#message").html("<p>File Upload Succeeded</p>"); } else { $("#message").html("<p>File Upload Failed!</p>"); } $("#message").append(data.message); } }); }); </script> </body> </html>
JAVASCRIPT
Use
FormData
to capture the fields. Note that instead of handling the button click we handle the submit event.$('#uploader').submit(function (event) { event.preventDefault(); $.ajax({ url: window.location.href + '/post', type: "POST", dataType: 'json', data: new FormData(this), processData: false, contentType: false, success: function (data) { //uncomment the next line to log the returned data in the javascript console // console.log(data); if (data.result === true) { $("#message").html("<p>File Upload Succeeded</p>"); } else { $("#message").html("<p>File Upload Failed!</p>"); } $("#message").append(data.message); } }); });
CONTROLLER
I've added some code that "reports" results to ajax and will display it on the upload page.
class Upload extends CI_Controller { public function __construct() { parent::__construct(); $this->load->helper(['form', 'url']); } public function index() { $this->load->view('upload_v'); } public function post() { $this->load->library("upload"); $this->upload->initialize(array( "upload_path" => './uploads/', 'allowed_types' => 'gif|jpg|png|doc|txt', "overwrite" => FALSE, "max_filename" => 300, "encrypt_name" => TRUE, )); $successful = $this->upload->do_upload('userfile'); if($successful) { $data = $this->upload->data(); $image_file = $data['file_name']; $msg = "<p>File: {$image_file}</p>"; $this->data_models->update($this->data->INFO, array("image" => $image_file)); } else { $msg = $this->upload->display_errors(); } echo json_encode(['result' => $successful, 'message' => $msg]); } }
This will upload your file. Your work probably isn't done because I suspect that your are not saving all the file info you need to the db. That, and I suspect you are going to be surprised by the name of the uploaded file.
I suggest you study up on how PHP handles file uploads and examine some of the similar codeigniter related questions on file uploads here on SO.
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