将几个数据库表组合在一起？ [英] Combining several database table together?

问题描述

我在数据库中有两个表 tour_foreign & tour_foreign_residence ，并且希望合并这两个表， PHP代码如下示例：

I have two tables tour_foreign&tour_foreign_residence in database and want merger this two table together that get output from PHP code as following example:

我的表和值it：

我想获取作为输出 tour_foreign.id = tour_foreign_residence.relation ：

一周的Istanbul_1 | 88888& 99999 $ 112233 $ 445566 |三晚两天| 15:29

一周的Istanbul_2 | 55555& 66666 $ 77777 |三晚两天| 12:03

一周的Istanbul_3 | 11111& 22222 $ 33333 $ 44444 |三晚两天| 12:03

One-week tour of Istanbul_1 | 88888 & 99999 $ 112233 $ 445566 | Three nights and two days | 15:29
One-week tour of Istanbul_2 | 55555 & 66666 $ 77777 | Three nights and two days | 12:03
One-week tour of Istanbul_3 | 11111 & 22222 $ 33333 $ 44444 | Three nights and two days | 12:03

我的尝试是这样，但它不会给我上面所需的东西：

My try is this but it don't give to me what that I want in above:

$this -> db -> query("
    SELECT
           @rownum := @rownum + 1 rownum,
           tour_foreign.id, 
           tour_foreign.name, 
           tour_foreign_residence.name_re,  
           tour_foreign.term,
           tour_foreign.time_go, 
           tour_foreign.time_back,
           tour_foreign.type_of_vehicle
    FROM   tour_foreign 
           INNER JOIN tour_foreign_residence 
             ON ( tour_foreign.id = tour_foreign_residence.relation )
           JOIN (SELECT @rownum := 0) r
    WHERE  tour_foreign.name LIKE "%' . $find . '%" 
            OR tour_foreign_residence.name_re LIKE "%' . $find . '%"    
")

如何解决？

推荐答案

不知道你为什么加入@rownum，它可能是搞乱你的结果集。尝试取出它，看看它是否工作。

Not sure why you are joining on @rownum, it might be messing with your result set. Try taking it out and see if it works.

您的内部连接看起来确定，除非我从来没有看到它与封装的括号，但我怀疑它会工作正常。要测试你的查询，你可以删除复杂的where子句，只是放置在类似tour_foreign.id = 1的地方。

Your inner join looks ok, except I have never seen it with the wrapped parens, but I suspect it will work as expected. To test your query you could remove the complicated where clause and just put something like where tour_foreign.id = 1.

有点像：

SELECT
    tf.*
FROM 
    tour_foreign AS tf
INNER JOIN
    tour_foreign_residence AS tfr
ON
    tfr.relation = tf.id
WHERE
    tf.id = 1

我为您的较长表名（tf和tfr）实现了别名，因为它们更容易使用。

I implemented aliases for your longer table names (tf, and tfr) as they are easier to work with.

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