CodeIgniter - 从视图内部调用函数 [英] CodeIgniter - Calling a function from inside a view

问题描述

是否可以从视图中调用位于控制器中的函数？

Is it possible to call a function which is located in a controller from a view?

这是我在我的控制器中的示例

This is what i have in my controller, as an example

function checkKeyExists($userid, $key){
}

然后在我的视图中，我有以下

Then inside my view i have the following

if(checkKeyExists($row->id, $role->key)){
}

但是当我运行它，它说，checkKeyExists没有定义。

But when I run it, it says that checkKeyExists is not defined.

如果任何人都可以让我知道我该怎么做，这将是巨大的。 >

If anyone can let me know how I could do this, that would be great.

推荐答案

视图并不意味着调用控制器操作。
颠倒你的逻辑，在控制器中调用该函数，并将其设置为发送到视图的变量。然后你可以有if语句检查你的视图模板中的变量。

Views are not meant to call controller actions. Reverse your logic, call that function in the controller and set it to a variable you sent to the view. Then you can have the if statement check that variable in your view template.

如果这不适合你，也许一个助手是你需要的： http://ellislab.com/codeigniter/user-guide/general/helpers.html

If that doesn't work for you, maybe a helper is what you need: http://ellislab.com/codeigniter/user-guide/general/helpers.html

这篇关于CodeIgniter - 从视图内部调用函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！