CodeIgniter form_dropdown选择值 [英] CodeIgniter form_dropdown selected value

问题描述

我有一个表单使用CI的form_dropdown从DB ...拉出一个数组。

  $ osValue ='id = osValue'; 
 echo form_dropdown（'os'，$ os，''，$ osValue）; 
 

当检查元素时，在用户代理中如下：

 < select name =osos> 
< option value =1> Windows XP 32位< / option> 
< option value =2> Windows XP 64位< / option> 
< option value =3> Windows Vista 32位< / option> 
< option value =4> Windows Vista 64位< / option> 
< option value =5> Windows 7 32位< / option> 
< option value =6> Windows 7 64位< / option> 
< option value =7> Server 2003 32位< / option> 
< option value =8> Server 2003 64位< / option> 
< option value =9> Server 2008 32位< / option> 
< option value =10> Server 2008 64位< / option> 
< option value =11> Linux< / option> 
< / select> 
  

我遇到的麻烦是只能将SELECTED值传递给变量。 / p>



当使用

时，我得到所有选项返回。

  var os = $ （'#osValue'）。html（）; 
  

或

  var os = $（'＃osValue'）。text（）; 
  

而且，在使用时，只返回值（由数据库传入的数字字符串） p>

  var os = $（'＃osValue'）。val（）; 
  

必须有一个或两个我缺少为了只有选择返回值。任何/所有的建议或帮助将非常感激。提前感谢！

解决方案

您有几个问题：

1）选择没有ID，但你正在查询id（你有一个out-of-placeos在那里; < select name =osos> ; 无效）

2）您不是在寻找已选择的选项

要修复，请选择 id ：

 < select name =osid =os> 
< option value =1> Windows XP 32位< / option> 
< option value =2> Windows XP 64位< / option> 
< option value =3> Windows Vista 32位< / option> 
< option value =4> Windows Vista 64位< / option> 
< option value =5> Windows 7 32位< / option> 
< option value =6> Windows 7 64位< / option> 
< option value =7> Server 2003 32位< / option> 
< option value =8> Server 2003 64位< / option> 
< option value =9> Server 2008 32位< / option> 
< option value =10> Server 2008 64位< / option> 
< option value =11> Linux< / option> 
< / select> 
  

并从jQuery中查询 ：

  var osval = $（'＃os option：selected'）
  

或，按名称查询：

  var osval = $（'[name =os ] option：selected'）
  

http://jsfiddle.net/5Vmxd/

I have a form using CI's form_dropdown that pulls an array from DB....

$osValue = 'id = "osValue"';
echo form_dropdown('os', $os, '', $osValue);

which, when inspecting the element, is as follows in the user agent...

<select name="os" os>
<option value="1">Windows XP 32-bit</option>
<option value="2">Windows XP 64-bit</option>
<option value="3">Windows Vista 32-bit</option>
<option value="4">Windows Vista 64-bit</option>
<option value="5">Windows 7 32-bit</option>
<option value="6">Windows 7 64-bit</option>
<option value="7">Server 2003 32-bit</option>
<option value="8">Server 2003 64-bit</option>
<option value="9">Server 2008 32-bit</option>
<option value="10">Server 2008 64-bit</option>
<option value="11">Linux</option>
</select>

What I'm having trouble with is being able to pass ONLY the SELECTED value into a variable.

I get ALL options returned, when using

var os = $('#osValue').html();

or

var os = $('#osValue').text();

And, only the value (a numerical string passed in by the DB) is returned when using

var os = $('#osValue').val();

There has to be a small piece or two that I'm missing in order to have only the selected value returned. Any/all advice or help would greatly appreciated. Thank you in advance!

解决方案

You have a couple of problems:

1) There is no ID on the select, yet you are querying for the id (you have an out-of-place "os" in there too; <select name="os" os> is not valid)

2) You aren't looking for which option has been selected

To fix, give the select an id:

<select name="os" id="os">
    <option value="1">Windows XP 32-bit</option>
    <option value="2">Windows XP 64-bit</option>
    <option value="3">Windows Vista 32-bit</option>
    <option value="4">Windows Vista 64-bit</option>
    <option value="5">Windows 7 32-bit</option>
    <option value="6">Windows 7 64-bit</option>
    <option value="7">Server 2003 32-bit</option>
    <option value="8">Server 2003 64-bit</option>
    <option value="9">Server 2008 32-bit</option>
    <option value="10">Server 2008 64-bit</option>
    <option value="11">Linux</option>
</select>

and query that from jQuery:

var osval = $('#os option:selected')

or, query by name:

var osval = $('[name="os"] option:selected')

http://jsfiddle.net/5Vmxd/

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