什么是测试CodeIgniter会话变量的正确方法？ [英] What is the proper way to test CodeIgniter session variable?

问题描述

取下面的代码片段。什么是测试以确保会话变量不为空的最好方法？

Take the following code snippet. What is the best way to test to make sure the session variable isn't empty?

<?php if ($this->session->userdata('userID')) {
   $loggedIn = 1;
}
else {
   $loggedIn = 0;
} ?>

如果稍后在我的脚本中，我调用以下命令，第一个打印正确，接收消息：未定义的变量：loggedIn

If later in my script, I call the following, the first prints properly, but on the second I receive Message: Undefined variable: loggedIn

<?php echo $this->session->userdata('userID'));
      echo $loggedIn; ?>

我试过使用！empty isset ，但两者都不成功。我也尝试使用 if（！（$ this-> session-> userdata（'userID'））向后执行if / then语句，但没有骰子。

I've tried using !empty and isset, but both have been unsuccessful. I also tried doing the if/then statement backwards using if (!($this->session->userdata('userID')), but no dice. Any thoughts?

推荐答案

尝试执行以下操作：

<?php 
$loggedIn = 0;
if ($this->session->userdata('userID') !== FALSE) {
   $loggedIn = 1;
}
?>

继续，您需要发布更多代码，以便在另一个作用域调用该变量。

If the error continues, you'll need to post more code in case you're calling that variable in another scope.

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