PHP / MySQL - 加入后分组结果? [英] PHP/MySQL - Group results after join?
问题描述
所以,我有三个表。电影,movies_genres和类型。我想要一个电影的它的Id,还加入它的类型的结果。我设法加入结果,但它不显示为我想要的。我不知道我要求的是否可能。
这是我的查询:
SELECT`movies`。*,GROUP_CONCAT(genres.id)AS genre_id,GROUP_CONCAT(genres.name)AS genre_name
FROM(`movies`)
INNER JOIN`movies_genres `
ON`movies_genres`.`movie_id` =`movies`.`id`
INNER JOIN`genres`
ON`genres`.`id` =`movies_genres`.`genre_id` WHERE`movies`.`id` = 19908
GROUP BY`movies`.`id`
查询由Codeigniters Active Record类生成,这里是Codeigniter代码,如果这有助于:
$ this-> db - > select('movies。*,GROUP_CONCAT(genres.id)AS genre_id,GROUP_CONCAT(genres.name)AS genre_name');
$ this-> db-> from('movies');
$ this-> db-> where('movies.id',$ movie_id);
$ this-> db-> join('movies_genres','movies_genres.movie_id = movies.id','inner');
$ this-> db-> join('genres','genres.id = movies_genres.genre_id','inner');
$ this-> db-> group_by('movies.id');
这是我当前得到的结果:
数组
(
[id] => 19908
[movie_title] => Zombieland
[overview] => ; An spooked guy ...
[genre_id] => 28,12,35,27
[genre_name] =>动作,冒险,喜剧,恐怖
)
这是我想要的:
Array
(
[id] => 19908
[movie_title] => Zombieland
[overview] =& ..
[genres] => array(
0 => array(
'id'=> 28,
'name'=> Action
),
1 => array(
'id'=> 12,
'name'=> Adventure
),
1 = array(
'id'=> 35,
'name'=> Comedy
),
1 => array(
'id'=> ; 27,
'name'=>恐怖
)
)
)
如果是,如何?
感谢一大早!
对不起的标题,我didn
您列出的查询将包含 其中 n =电影#),而你想要的查询将有更多的行(#of movie_genre的条目)。
请考虑:
获得后,只需运行你的结果(例如 $ result
)数组:
foreach($ result as& $ row)
{
//分割逗号
$ gi_elements = explode(',',$ row ['genre_id' ]);
$ gn_elements = explode(',',$ row ['genre_name']);
// Build genre
$ row ['genre'] = array();
for($ i = 0; $ i {
$ row ['genre'] [] = array('id'=& $ gi_elements [$ i],'name'=> $ gn_elements [$ i]);
}
//清除
unset($ row ['genre_id']);
unset($ row ['genre_name']);
}
之后,$ results将完全按照你的愿望,而不需要额外的数据库工作。 / p>
编辑: 修正了一些错别字。
So, i have three tables. Movies, movies_genres and genres. I want to get a movie by it's Id, and also join it's genres in the result. I managed to join the results, but it doesn't display as i want it to. I'm not sure if what i'm asking is possible.
This is my query:
SELECT `movies`.*, GROUP_CONCAT(genres.id) AS genre_id, GROUP_CONCAT(genres.name) AS genre_name
FROM (`movies`)
INNER JOIN `movies_genres`
ON `movies_genres`.`movie_id` = `movies`.`id`
INNER JOIN `genres`
ON `genres`.`id` = `movies_genres`.`genre_id` WHERE `movies`.`id` = 19908
GROUP BY `movies`.`id`
The query was generated by Codeigniters Active Record class, here is the Codeigniter code if that helps:
$this->db->select('movies.*, GROUP_CONCAT(genres.id) AS genre_id, GROUP_CONCAT(genres.name) AS genre_name');
$this->db->from('movies');
$this->db->where('movies.id', $movie_id);
$this->db->join('movies_genres', 'movies_genres.movie_id = movies.id', 'inner');
$this->db->join('genres', 'genres.id = movies_genres.genre_id', 'inner');
$this->db->group_by('movies.id');
Here is the result i'm currently getting:
Array
(
[id] => 19908
[movie_title] => Zombieland
[overview] => An easily spooked guy...
[genre_id] => 28,12,35,27
[genre_name] => Action,Adventure,Comedy,Horror
)
And this is what i want:
Array
(
[id] => 19908
[movie_title] => Zombieland
[overview] => An easily spooked guy...
[genres] => array(
0 => array(
'id' => 28,
'name' => Action
),
1 => array(
'id' => 12,
'name' => Adventure
),
1 => array(
'id' => 35,
'name' => Comedy
),
1 => array(
'id' => 27,
'name' => Horror
)
)
)
Is this possible, and if so, how?
Thanks a bunch in advance!
And sorry for the confusing title, i didn't know quite how to put it.
The query you listed will have n rows (where n = # of movies) whereas the query it seems you want will have many more rows (# of movie_genre's entries). You're probably better off leaving that query as it is, and doing some post processing.
Consider:
After you get it, just run your result (e.g. $result
) array through something like:
foreach($result as &$row)
{
// Split over commas
$gi_elements = explode(',', $row['genre_id']);
$gn_elements = explode(',', $row['genre_name']);
// Build genre
$row['genre'] = array();
for($i=0; $i<count($gi_elements); $i++)
{
$row['genre'][] = array('id' => $gi_elements[$i], 'name' => $gn_elements[$i]);
}
// Cleanup
unset($row['genre_id']);
unset($row['genre_name']);
}
Afterwards, $results will look exactly as you wish without extra database work.
EDIT: Fixed some typos.
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