代码标记的分页错误 [英] Error in pagination of codeigniter

问题描述

在模型/ rci_model.php中

In model/rci_model.php

public function record_count() {
    return $this->db->count_all("produk");
}

    public function fetch_countries($limit, $start) {
        $this->db->limit($limit, $start);
         $query=$this->db->query("SELECT * FROM produk WHERE id_kategori='Men' order by nama_produk ASC");
            return $query->result();

        if ($query->num_rows() > 0) {
            foreach ($query->result() as $row) {
                $data[] = $row;
            }
            return $data;
        }
        return false;
   }

在控制器/ sandal_clarudo.php

In controller/sandal_clarudo.php

function sandals_for_men(){
    $data['seo'] = $this->rci_model->tampil_meta(22);
    $this->load->view('head', $data);
    $config = array();
    $config["base_url"] = "http://localhost/clarudo/index.php/sandal_clarudo/sandals_for_men/";
    $config["total_rows"] = $this->rci_model->record_count();
    $config["per_page"] = 5;
    $config["uri_segment"] = 3;

    $this->pagination->initialize($config);

    $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
    $data["results"] = $this->rci_model->
        fetch_countries($config["per_page"], $page);
    $data["links"] = $this->pagination->create_links();
    $this->load->view('men', $data);
    $this->load->view('footer');
}

在视图/ men.php

In view/men.php

<?php
foreach($results as $t) {
$t->nama_produk
}
<div><?php echo $links; ?></div>

我想显示只有category ='Men'的产品，但在我的代码显示所有类别

I want to show product that has category = 'Men' only, but in my code showing all category product,it make me confused,help me please.

推荐答案

只需尝试使用此代码为您的fetch_countries（）函数

Just try with this code for your fetch_countries() function

public function fetch_countries($limit, $start) {
   $this->db->limit($limit, $start);
   $query = $this->db->query("SELECT * FROM produk WHERE id_kategori='Men' order by nama_produk ASC");
   return $query->result();
}

这里发生的是你返回结果，如果可用或返回false

what happens here is you are return results if available or return false

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