从服务器路径获取URL [英] Get URL from server path

问题描述

我使用Codeigniter的文件上传库上传文件，并尝试将该URL插入数据库。 Codeigniter仅在使用 $ this-> upload-> data（）时提供server_path，这不能用于向用户显示图像。

I am uploading a file using Codeigniter's File Uploading Library and trying to insert the URL into the database. Codeigniter only supplies the server_path when using $this->upload->data(), which isn't usable for displaying the image to users.

我通常可以做一些像 base_url（'uploads）。 '/'。 $ data ['file_name'] 但我将图像存储在每个帖子的文件夹中。

I could normally just do something like base_url('uploads) . '/' . $data['file_name'] but I am storing the images in a folder for each post.

例如， c $ c> C：/xampp/htdocs/site/uploads/32/image.jpg 作为full_path，如何将其转换为 http://mysite.com /uploads/32/image.jpg

For example, I am getting C:/xampp/htdocs/site/uploads/32/image.jpg as the full_path, how can I convert this to http://mysite.com/uploads/32/image.jpg

唯一要注意的事情是使用正则表达式，但我觉得有是PHP函数还是Codeigniter函数来帮助这个？

The only thing that comes to mind is using a regular expression, but I feel like there has to be PHP function or Codeigniter function to help with this?

如何将服务器路径转换成正确的URL？

How can I convert the server path into the correct URL?

推荐答案

您可以使用$ _SERVER ['HTTP_HOST'];获取url。使用您的帖子的ID，您可以这样构建您的路径：

You can use $_SERVER['HTTP_HOST']; to get the url. Using the ID for your post, you can construct your path like so:

$url = "http://" . $_SERVER['HTTP_HOST'] . "/" . $id . "/" . basename($data['file_name']);

basename（）函数返回路径中最后一个/之后的所有内容。

the basename() function returns everything after the last / in your path.

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