Java比较字符串 [英] Java Compare Strings

问题描述

 /**
 * A method to compare Strings
 * @param arg1
 * @param arg2
 * @return 
 */
public boolean myQuickCompare(String arg1, String arg2) {
    boolean a = arg1.length() == arg2.length();
    if (a) {
        for (int b = 0; b > arg1.length(); b++) {
            if (arg1.charAt(b) != arg2.charAt(b)) {
                a = false;
            }
        }
    }
    return a;
}

我理解for循环是错误的，b永远不会大于字符串的长度。您将如何解决这个问题？

I understand that the for loop is the wrong way around, b will never be greater than the length of the string. How would you correct this problem?

您对a和b有什么明智的变量名？

What sensible variable names would you give for a and b?

推荐答案

p>使用 arg1.equals（arg2）。
无需自定义函数。不要试图超越Java的开发人员。大多数时候，他们赢了。

Use arg1.equals(arg2). No need for custom functions. Don't try to outsmart the developers of Java. Most of the time, they win.

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