在一次调用中将ArrayList.toString()转换回ArrayList [英] convert ArrayList.toString() back to ArrayList in one call

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问题描述

我有一个 toString()表示 ArrayList

toString()值复制到剪贴板,我想将它复制回我的IDE编辑器,并创建 ArrayList 实例在一行。事实上,我真正做的是这样:

Copying the toString() value to clipboard, I want to copy it back into my IDE editor, and create the ArrayList instance in one line. In fact, what I'm really doing is this:


  • 我的ArrayList.toString()有我需要设置单元测试的数据。

  • 我想将此ArrayList.toString()复制到我的编辑器中,以构建针对此边缘情况的测试

  • 我不想解析
  • my ArrayList.toString() has data I need to setup a unit test.
  • I want to copy this ArrayList.toString() into my editor to build a test against this edge case
  • I don't want to parse anything by hand

以下不工作:


  • Arrays.asList()

  • google collections Lists.newArrayList()

  • Arrays.asList()
  • google collections Lists.newArrayList()

建议?

推荐答案

Substring 大括号, / / docs / api / java / lang / String.html#split%28java.lang.String%29rel =nofollow noreferrer / code>(逗号和空格),最后将其提供给 Arrays#asList()

Substring the braces away, split it on , (comma and space) and finally feed it to Arrays#asList().

 String s = "[15.82, 15.870000000000001, 15.92, 16.32, 16.32, 16.32, 16.32, 17.05, 17.05, 17.05, 17.05, 18.29, 18.29, 19.16]";
 List<String> list = Arrays.asList(s.substring(1, s.length() - 1).split(", "));

请注意,这将适用于您的特定情况,但不是在所有情况下。例如,您可以有一个字符串列表,其中至少一个字符串包含后续的逗号和空格。然后拆分将失败。

Note that this will work in your particular case, but not in all circumstances. You may for example have a list of strings of which at least one contains a subsequent comma and space. The split would then fail.

这篇关于在一次调用中将ArrayList.toString()转换回ArrayList的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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