基于两个参数同时收集排序 [英] Collection sorting in basis of two parameters simultaneously
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问题描述
我有一个类有两个日期字段说:
class TestData {
Date activation;
日期timeStamp;
}
我想根据 activation
日期,如果它们相等,则基于 timestamp
即max(激活)和max(timeStamp)。
代码我试过的只有fetch max(激活)
public class CollectionSort {
public static void main(String [] args){
List< TestData> testList = new ArrayList< TestData>();
Collections.sort(testList,new Comparator< TestData>(){
@Override
public int compare(TestData t1,TestData t2){
int result = 0;
if(t1.getActivation()。before(t2.getActivation())){
result = 1;
}
返回结果;
}
});
System.out.println(First object is+ testList.get(0));
}
}
任何帮助将非常感激。
感谢
解决方案
b
Collections.sort(yourList,new Comparator< TestData>(){
public int compare(TestData o1,TestData o2){
int date1Diff = o1.getActivation()。compareTo(o2.getActivation());
return date1Diff == 0?
o1.geTimestamp()。compareTo(o2.getTimestamp()):
date1Diff;
}
});
I have a class with two date fields say:
class TestData {
Date activation;
Date timeStamp;
}
I want to sort the list of the above class on basis of activation
date and if they are equal then on basis of timestamp
i.e. max(activation) and max(timeStamp).
Code I tried is as follws which only fetch max(activation)
public class CollectionSort {
public static void main(String[] args) {
List<TestData> testList = new ArrayList<TestData>();
Collections.sort(testList, new Comparator<TestData>() {
@Override
public int compare(TestData t1, TestData t2) {
int result = 0;
if (t1.getActivation().before(t2.getActivation())) {
result = 1;
}
return result;
}
});
System.out.println("First object is " + testList.get(0));
}
}
Any help would be greatly appreciated.
Thanks
解决方案
This would do it.!
Collections.sort(yourList, new Comparator<TestData>() {
public int compare(TestData o1, TestData o2) {
int date1Diff = o1.getActivation().compareTo(o2.getActivation());
return date1Diff == 0 ?
o1.geTimestamp().compareTo(o2.getTimestamp()) :
date1Diff;
}
});
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