如何迭代两个多地图并打印文件中的差异？ [英] How to iterate two multi maps and print the difference in file?

问题描述

我有两个多重映射，如下所示：

  ListMultimap< String，String> source_multimap = ArrayListMultimap.create（）; 
 ListMultimap< String，String> target_multimap = ArrayListMultimap.create（）; 
 
 for（SwiftTagListBlock s：source_tagListBlock）{
 Iterator< Tag> sourcetag_iterator = s.tagIterator（）; 
 
 while（sourcetag_iterator.hasNext（））{
 Tag tag =（Tag）sourcetag_iterator.next（）; 
 source_multimap.put（tag.getName（），tag.getValue（））; 
} 
} 
 for（SwiftTagListBlock t：target_tagListBlock）{
 Iterator< Tag> targettag_iterator = t.tagIterator（）; 
 
 while（targettag_iterator.hasNext（））{
 Tag tag =（Tag）targettag_iterator.next（）; 
 target_multimap.put（tag.getName（），tag.getValue（））; 
} 
} 
  

它会给我们一对键值键和多值。我想比较如下：

if（mulimap1.get（key）.equals（multimap2.get（key）））然后比较集合的值。

解决方案

if（multimap1.getValues（）！= multimap2.getValues code> Sets.intersection（source_multimap.keySet（），target_multimap.keySet（））forEach（key - > {
Multiset< String> multiset1 = ImmutableMultiset.copyOf（source_multimap.get ;
Multiset< String> multiset2 = ImmutableMultiset.copyOf（target_multimap.get（key））;
System.out.println（key +has values different：+ Multisets.union Multisets.difference（multiset1，multiset2），
Multisets.difference（multiset2，multiset1）
））;
}）;

输出示例：

  source：{a = [1,1]，b = [1]} 
 target：{a = [1,2]，b = [1， 2]，c = [1]} 
a的值不同：[1,2] 
b的值不同：[2] 
  

并且如果你想要包含差异的唯一的映射替换 Sets.intersection 与集.union ：

  source：{a = [1,1 ]，b = [1]} 
目标：{a = [1,2]，b = [1,2]，c = [1]} 
a具有不同的值：[1,2] 
b的值不同：[2] 
c的值不同：[1] 
  

I have two multimaps as below :

ListMultimap<String, String> source_multimap = ArrayListMultimap.create();
ListMultimap<String, String> target_multimap = ArrayListMultimap.create();

for (SwiftTagListBlock s : source_tagListBlock) {
    Iterator<Tag> sourcetag_iterator = s.tagIterator();

    while (sourcetag_iterator.hasNext()) {
        Tag tag = (Tag) sourcetag_iterator.next();
        source_multimap.put(tag.getName(), tag.getValue());
    }
}
for (SwiftTagListBlock t : target_tagListBlock) {
    Iterator<Tag> targettag_iterator = t.tagIterator();

    while (targettag_iterator.hasNext()) {
        Tag tag = (Tag) targettag_iterator.next();
        target_multimap.put(tag.getName(), tag.getValue());
    }
}

It will give us pair of key-value with single-keys and multiple-values. I want to compare like this below :

if(mulimap1.get(key).equals(multimap2.get(key))) then compare the collection for values. if(multimap1.getValues()!=multimap2.getValues()) then print the values different.

解决方案

Sets.intersection(source_multimap.keySet(), target_multimap.keySet()).forEach(key -> {
    Multiset<String> multiset1 = ImmutableMultiset.copyOf(source_multimap.get(key));
    Multiset<String> multiset2 = ImmutableMultiset.copyOf(target_multimap.get(key));
    System.out.println(key + " has values different: " + Multisets.union(
            Multisets.difference(multiset1, multiset2),
            Multisets.difference(multiset2, multiset1)
    ));
});

Example output:

source: {a=[1, 1], b=[1]}
target: {a=[1, 2], b=[1, 2], c=[1]}
a has values different: [1, 2]
b has values different: [2]

And if you want to include differences for keys unique to either map substitute Sets.intersection with Sets.union:

source: {a=[1, 1], b=[1]}
target: {a=[1, 2], b=[1, 2], c=[1]}
a has values different: [1, 2]
b has values different: [2]
c has values different: [1]

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