测试颜色是否相等 [英] Testing if colors equal

问题描述

我正在从斯坦福演讲在iTunes U（仍然很漂亮的绿色）的突围作业，并陷入了一个咆哮。我试图设置一个点值为不同的彩色砖，所以我可以计算一个分数，但我的if的似乎不工作。我有一种感觉，getColor（）不返回值，我认为是;我创建了一个状态标签来显示它的返回，但我仍然不能弄清楚如何测试。

以下是我正在处理的一段代码：

  if（collider！= null&& collider！= paddle）{
 remove（scoreLabel）; 
 vy = -vy; 
 color brickColor = collider.getColor（）; 
 add（new GLabel（+ collider.getColor（），10，12））; 
 double temp = brickVal（brickColor）* scoreMultiplier; 
 score + = Math.abs（temp）; 
 addScoreboard（）; 
 remove（collider）; 
} 
} 
 
 private double brickVal（Color c）{
 if（c.equals（Color.RED））{
 return 10.0; 
} else if（c == Color.ORANGE）{
 return brickVal = 8.0; 
} else if（c == Color.YELLOW）{
 return brickVal = 6.0; 
} else if（c == Color.GREEN）{
 return brickVal = 4.0; 
} else if（Color.CYAN.equals（c））{
 return brickVal = 2.0; 
} else if（c == Color.MAGENTA）{
 return brickVal = 1.0; 
} else {
 return 1.0; 
} 
} 
  

如果你需要完整的代码让我知道。 / p>

解决方案

使用 Color.X.equals（c）就像 c == Color.X 。

您也可以使用 c.equals（Color.X），就像你为 Color.RED 所做的那样，但是很多人喜欢用另一种方法来保护<对于 c 为 null 的情况， NullPointerException b $ b

I'm working on the Breakout assignment from the Stanford lectures on iTunes U (still pretty green) and ran into a snarl. I'm trying to set a point value for the different colored bricks so I can calculate a score but my if's don't seem to work. I have a feeling that getColor() isn't returning the value that I think it is; I created a status label to show my what it's returning but I still can't figure out how to test for that. More than likely it's something simple I'm missing or just don't know of yet.

Here's a snippet of the bit I'm working on:

if (collider != null && collider != paddle) {
        remove(scoreLabel);
        vy = -vy;
        Color brickColor = collider.getColor();
        add(new GLabel("" + collider.getColor(), 10, 12));
        double temp = brickVal(brickColor) * scoreMultiplier;
        score += Math.abs(temp);
        addScoreboard();
        remove(collider);
    }
}

private double brickVal(Color c) {
    if (c.equals(Color.RED)) {
        return 10.0;
    } else if (c == Color.ORANGE) {
        return brickVal = 8.0;
    } else if (c == Color.YELLOW) {
        return brickVal = 6.0;
    } else if (c == Color.GREEN) {
        return brickVal = 4.0;
    } else if (Color.CYAN.equals(c)) {
        return brickVal = 2.0;
    } else if (c == Color.MAGENTA) {
        return brickVal = 1.0;
    } else {
        return 1.0;
    }
}

If you need the full code let me know.

解决方案

Use Color.X.equals(c) for your if cases that are like c == Color.X. You're testing if the objects are the same instance, instead of if they're considered to be equal to each other.

You could also use c.equals(Color.X) like you did for Color.RED, however many people prefer the other way to safeguard against a NullPointerException for cases where c is null.

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