R，knitr，xtable，交替行颜色 [英] R, knitr, xtable, alternating row colors

问题描述

我试图使用 knitr 在交替行颜色中生成一个带有 xtable 的表。我可以在PDF输出中打印一个表，但不能完全弄清楚 xtable add.to.row 命令c>手动以及 colortbl 包。

I'm trying to produce a table with xtable in R using knitr with alternating row colors. I can print a table in the PDF output but can't quite figure out the add.to.row command in the xtable manual along with the colortbl package.

推荐答案

使用底部的代码生成。我希望你不要打破你的眼睛检测浅灰色（我几乎有，在我的一个屏幕上）。

This figure was produced using the code at the bottom. I hope you don't break your eyes detecting the light grey color (I almost have, on one of my screens).

library(xtable)
mydf <- data.frame(id = 1:10, var1 = rnorm(10), var2 = runif(10))
rws <- seq(1, (nrow(mydf)-1), by = 2)
col <- rep("\\rowcolor[gray]{0.95}", length(rws))
print(xtable(mydf), booktabs = TRUE,
      add.to.row = list(pos = as.list(rws), command = col))

关键是定义行索引（ rws ）及其各自的颜色（ col ）。如果你想让行之间的颜色不同，你需要使用粘贴。

The key is to define row indices (rws) and their respective colors (col). If you want colors to differ between rows, you'll need to play around with paste.

\documentclass[a4paper]{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[english]{babel}
\usepackage{booktabs}
\usepackage{colortbl, xcolor}

\begin{document}

<<do_table, results = "asis">>=
library(xtable)
mydf <- data.frame(id = 1:10, var1 = rnorm(10), var2 = runif(10))
rws <- seq(1, (nrow(mydf)), by = 2)
col <- rep("\\rowcolor[gray]{0.95}", length(rws))
print(xtable(mydf), booktabs = TRUE, 
   add.to.row = list(pos = as.list(rws), command = col))
@

\end{document}

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