WPF颜色插值 [英] WPF Color interpolation

问题描述

我试图绘制一个WPF控件的背景基于调色板，其中每个颜色已分配值（例如红= 0，暗绿= 10，绿色= 20，LightGreen = 30）和用户选择的值25），其将给出所得到的颜色。我希望生成的颜色是2个最接近的颜色值之间的插值（例如，值为25，它应该在绿色和LightGreen之间给出颜色）

我想在WPF中使用现有的LinearGradientBrush;设置GradientStops，偏移并获得指定值的颜色。是否有办法做到这一点，还是应该实现自己的颜色插值函数？

谢谢。

使用LinearGradientBrush听起来像会有一点开销。没有知识。

我假设你的调色板的值为了简单起见可以被10整除。

  public static Color GetColor（int value）
 {
 int startIndex =（value / 10）* 10; 
 int endIndex = startIndex + 10; 
 
 color startColor = Palette [startIndex]; 
 color endColor = Palette [endIndex]; 
 
 float weight =（value  -  startIndex）/（float）（endIndex  -  startIndex）; 
 
 return Color.FromArgb（
（int）Math.Round（startColor.R *（1  -  weight）+ endColor.R * weight），
（int） Round（startColor.G *（1  -  weight）+ endColor.G * weight），
（int）Math.Round（startColor.B *（1- weight）+ endColor.B * weight） 
 
} 
  

如果定义的颜色不能被10整除，发现开始和结束的颜色会更复杂一些。

I am trying to paint a WPF control's background based on a palette where each color has been assigned with values (e.g. Red = 0, DarkGreen = 10, Green = 20,LightGreen =30) and a user-selected value (e.g. 25) that would give the resulting color. I would like the resulting color to be an interpolation between the 2 nearest color values (e.g. for a value of 25 it should give a color between Green and LightGreen)

For that I'm thinking of using the existing LinearGradientBrush in WPF; set the GradientStops, offsets and get the color at a specified value . Is there a way to do this or should I implement my own color interpolation function?

Thanks.

解决方案

Using the LinearGradientBrush sounds like it would have a bit of an overhead. No knowledge though. A color interpolation function isn't that hard to write though.

I'm assuming your palettes have values that are divisible by 10 for simplicity.

public static Color GetColor(int value)
{
    int startIndex = (value/10)*10;
    int endIndex = startIndex + 10;

    Color startColor = Palette[startIndex];
    Color endColor = Palette[endIndex];

    float weight = (value - startIndex)/(float)(endIndex - startIndex);

    return Color.FromArgb(
        (int)Math.Round(startColor.R * (1 - weight) + endColor.R * weight),
        (int)Math.Round(startColor.G * (1 - weight) + endColor.G * weight),
        (int)Math.Round(startColor.B * (1 - weight) + endColor.B * weight));

}

If the defined colors are not divisible by 10 the logic to find the start and end colors will be a bit more complex.

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