Java - toString到颜色 [英] Java - toString to Colour

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本文介绍了Java - toString到颜色的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在努力工作这一整天。

I have been trying to work this out all day.

基本上,我做了一个for循环,将条目添加到数组列表。其中一个条目是颜色可变。我使用 random.nextInt 为颜色构造函数的红色,绿色和蓝色部分创建新值。我还设置了一个 toString 方法,所以我可以看到值进入arraylist。

Basically I have made a for loop which adds entries into an arraylist. One of the entries is a "Colour" varible. I have used the random.nextInt to create new values for the red, green and blue parts of the colour constructor. I have also set a toString method so I can see the values going into the arraylist.

问题是:

当打印出来时,我得到: java.awt.Color [r = 248,g = 103,b = 53]

When printing out I get : java.awt.Color[r=248,g=103,b=53]

我明白为什么会这样,可以改变,所以输出说单词橙色或绿色或紫色取决于什么随机rgb值。

and I understand why that is so, I'm just wondering how I can change that so the output says the word "orange" or "green" or "purple" depending on what the random rgb values are.

我在这里查看,我发现我可以使用 getRGB 方法和解析, ...

I looked on here and I found that I could possibly use the getRGB method and parsing and thats where I get stuck... any help would be great :)

推荐答案

我从来没有真正遇到过你要求的东西,但这将为你工作吗? (您可能需要根据您的需要添加更多颜色):

I've never really came across something you're asking for, but would this work for you? (You might need to add more colors for your needs) :

public final class ColorUtil {

    static private HashMap<String,Color> KNOWNCOLORS = new HashMap<String,Color>();

    static {
        KNOWNCOLORS.put("black",     Color.black);
        KNOWNCOLORS.put("darkgray",  Color.darkGray);
        KNOWNCOLORS.put("lightgray", Color.lightGray);
        KNOWNCOLORS.put("white",     Color.white);
        KNOWNCOLORS.put("red",       Color.red);
        KNOWNCOLORS.put("blue",      Color.blue);
        KNOWNCOLORS.put("green",     Color.green);
        KNOWNCOLORS.put("pink",      Color.pink);
        KNOWNCOLORS.put("cyan",      Color.cyan);
        KNOWNCOLORS.put("purple",    Color.magenta);
        KNOWNCOLORS.put("orange",    Color.orange);
        KNOWNCOLORS.put("yellow",    Color.yellow);
        // add more here
    }


    static public String getBestColorName(Color c) {
        int dist, diff = Integer.MAX_VALUE;
        String colorName = toHex(c);
        Color c2;

        for (String name : KNOWNCOLORS.keySet()) {
            c2 = KNOWNCOLORS.get(name);
            dist = Math.abs(c.getRed() - c2.getRed())
                    + Math.abs(c.getGreen() - c2.getGreen()) 
                    + Math.abs(c.getBlue() - c2.getBlue())
                    + Math.abs(c.getAlpha() - c2.getAlpha());

            if (dist < diff) {
                diff = dist;
                colorName = name; 
            }
        }

        return colorName;
    }

    static public int getColorValue(Color c) {
        return (c.getAlpha() << 24) 
            | (c.getRed() << 16)
            | (c.getGreen() << 8) 
            | (c.getBlue()); 
    }

    static public String toHex(Color c) {
        StringBuilder b = new StringBuilder();
        if (c.getAlpha() < 255) {
            b.append(padLeft(Integer.toString(c.getAlpha(), 16), 2));
        }
        b.append(padLeft(Integer.toString(c.getRed(), 16), 2));
        b.append(padLeft(Integer.toString(c.getGreen(), 16), 2));
        b.append(padLeft(Integer.toString(c.getBlue(), 16), 2));

        return b.toString();
    }

    static private String padLeft(String s, int n) {
        return String.format("%1$#" + n + "s", s).replace(" ", "0");
    }

    private ColorUtil() {}



    static public void main(String...args) {
        Color c;

        for (String name : KNOWNCOLORS.keySet()) {
            if (!name.equals(getBestColorName(KNOWNCOLORS.get(name)))) {
                System.out.println("*** ERR!! Could not match color " + name);
            } 
        }

        for (int i=0; i<30; i++) {
            c = new Color((int) (Math.random() * 256), (int) (Math.random() * 256), (int) (Math.random() * 256));

            System.out.println("Color " + toHex(c) 
                 + " (" + c.getAlpha() + "," + c.getRed() + "," + c.getGreen() + "," + c.getBlue() + ")"
                 + " = " + getBestColorName(c));
        }

        System.out.println("Done!");
    }

}

输出示例:

Color e75848 (255,231,88,72) = red
Color 6f4854 (255,111,72,84) = darkgray
Color 5dc6af (255,93,198,175) = lightgray
Color 190971 (255,25,9,113) = darkgray
Color 8ef300 (255,142,243,0) = yellow
Color c2ec5b (255,194,236,91) = lightgray
Color 998794 (255,153,135,148) = lightgray
Color 328d06 (255,50,141,6) = darkgray
Color 223d03 (255,34,61,3) = darkgray
Color 51dfea (255,81,223,234) = cyan
Color baa801 (255,186,168,1) = orange
Color 8370d4 (255,131,112,212) = lightgray
Color 7766bd (255,119,102,189) = lightgray
Color 35024b (255,53,2,75) = darkgray
Color cdbfad (255,205,191,173) = lightgray
Color 5e3a21 (255,94,58,33) = darkgray
Color 11af5d (255,17,175,93) = darkgray
Color 480995 (255,72,9,149) = darkgray
Color 04adab (255,4,173,171) = cyan
Color 98641c (255,152,100,28) = darkgray
Color 3ef68c (255,62,246,140) = cyan
Color 4d091a (255,77,9,26) = darkgray
Color 56117d (255,86,17,125) = darkgray
Color 1a00ea (255,26,0,234) = blue
Color 2ffd3e (255,47,253,62) = green
Color 9a918b (255,154,145,139) = lightgray
Color 6f8f0e (255,111,143,14) = darkgray
Color 5f3e25 (255,95,62,37) = darkgray
Color 914e79 (255,145,78,121) = darkgray
Color 57f88b (255,87,248,139) = cyan
Done!

这篇关于Java - toString到颜色的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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