在Eclipse上的随机颜色打印 [英] Random Color Print in java on Eclipse
本文介绍了在Eclipse上的随机颜色打印的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我创建了一个随机彩色游戏，部分代码是：
public static void getARandomColor $ b {
System.out.println（）;
System.out.println（Your random color is ...）;
// red
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
RED = MY_RANDOM;
// green
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
GREEN = MY_RANDOM;
// blue
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
BLUE = MY_RANDOM;
// combine ...
System.out.println（你的颜色是r：+ RED +，g：+ GREEN
+，b：+ BLUE + ！）;
System.out.println（）;
}
所以一切正常，但我想进一步，紧接着
System.out.println（您的颜色是r：+ RED +，g：+ GREEN
+，b：+ BLUE +！ ）;
import java.awt.Color;
import java.util.Random;
import java.util.Scanner;
import javax.swing.JTextArea;
/ **
*我的RNG游戏有多个选择;数组，硬币和颜色。
* /
public class RandomNumberGenerator
{
//所有颜色可用
private static final int COLOR_MAX = 256;
private static int RED，GREEN，BLUE;
private static int MY_RANDOM;
static Scanner MY_CONSOLE = new Scanner（System.in）;
static RANDOM_NUMBER = new Random（）;
private static int [] RANDOM_NUM_ARRAY;
/ **
*让游戏工作！主系统的游戏。
* /
public static void main（String [] args）
{
while（true）
{
//菜单简介
System.out.println（Welcome to the Random Generation Game！）;
System.out.println（Chose an option below：）;
System.out.println（）;
// menu
System.out.println（1。生成一个随机数字数组！
System.out.println（2.翻转硬币！）;
System.out.println（3。创建随机颜色！）;
System.out.println（4. Exit！）;
int option = MY_CONSOLE.nextInt（）;
//选择哪个选项？
//随机数组游戏
if（option == 1）
{
createYourRandomArray（）;
}
//硬币游戏
else if（option == 2）
{
flipTheCoinGame（）;
}
//颜色游戏
else if（option == 3）
{
getARandomColor（）;
}
//退出？
//我试图将1,2,3和4放入常量，但是代码
//不会读取常量后面的值，而是进入
// my else。 ..
else if（option == 4）
{
break;
}
//错误！
else
{
System.out.println（Invalid！Choose 1-4！）;
}
}
//关闭控制台
MY_CONSOLE.close（）;
System.out.println（）;
//游戏结束文本
System.out.println（see ya later！）;
}
//随机数组游戏工程
/ **
*此处创建的随机数组数组。
* /
public static void createYourRandomArray（）
{
// elements？
System.out.println（你想在你的数组中有多少个元素？
int element = MY_CONSOLE.nextInt（）;
MY_CONSOLE.nextLine（）;
// min？
System.out.println（Min value？）;
int myMin = MY_CONSOLE.nextInt（）;
MY_CONSOLE.nextLine（）;
// max？
System.out.println（Max？）;
int myMax = MY_CONSOLE.nextInt（）;
MY_CONSOLE.nextLine（）;
// random works
RANDOM_NUM_ARRAY = new int [element];
//打开
System.out.println（）;
System.out.print（[）;
//
for（int i = 0; i
MY_RANDOM = RANDOM_NUMBER.nextInt（myMax - myMin + 1）;
MY_RANDOM + = myMin;
RANDOM_NUM_ARRAY [i] ++;
RANDOM_NUM_ARRAY [i] = MY_RANDOM;
if（i
System.out.print（RANDOM_NUM_ARRAY [i] +，）;
}
else
{
System.out.print（RANDOM_NUM_ARRAY [i]）;
}
}
System.out.println（]）;
System.out.println（）;
}
/ **
*这里创建的Flip硬币游戏部分。
* /
public static void flipTheCoinGame（）
{
int coinTail = 0;
int coinHead = 0;
System.out.println（你想要多少次翻转硬币？
int youFlip = MY_CONSOLE.nextInt（）;
System.out.println（）;
for（int i = 0; i< youFlip; i ++）
{
MY_RANDOM = RANDOM_NUMBER.nextInt（2）;
if（MY_RANDOM == 1）
{
System.out.print（heads，）;
coinHead ++;
}
//如果不是头，那么tails
else
{
System.out.print（tails，）;
coinTail ++;
}
}
System.out.println（）;
System.out.println（你翻转+ coinHead +头和+ coinTail
+尾！
System.out.println（）;
}
//生成RGB形式的颜色。
/ **
*随机颜色生成器。创建随机RGB。
* /
public static void getARandomColor（）
{
System.out.println（）;
System.out.println（Your random color is ...）;
// red
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
RED = MY_RANDOM;
// green
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
GREEN = MY_RANDOM;
// blue
MY_RANDOM = RANDOM_NUMBER.nextInt（COLOR_MAX）;
BLUE = MY_RANDOM;
// combine ...
System.out.println（你的颜色是r：+ RED +，g：+ GREEN
+，b：+ BLUE + ！）;
System.out.println（）;
}
}
解决方案
I认为没有方法在java中获取颜色的名称。所以你创建以下方法。
String getColorName（int r，int g，int b）{switch（r）{case 0：switch（g）{
case 0：switch（b）
{
case 0：returnblack
break;
case 128：returnNavy;
break;
case 255：returnBlue;
break;
//继续所有颜色$ b
$ b}
}
}
你可以参考它的颜色名称和RGB值。
在此输入链接描述
I have created a Random Color game and part of the code goes is:
public static void getARandomColor()
{
System.out.println();
System.out.println("Your random color is...");
// red
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
RED = MY_RANDOM;
// green
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
GREEN = MY_RANDOM;
// blue
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
BLUE = MY_RANDOM;
// combinations...
System.out.println("Your color is r: " + RED + ", g: " + GREEN
+ ", b: " + BLUE + "!");
System.out.println();
}
So everything works that is shown, but I want to go further and add text right after the
"System.out.println("Your color is r: " + RED + ", g: " + GREEN
+ ", b: " + BLUE + "!");" line which becomes the random color given.
full code
import java.awt.Color;
import java.util.Random;
import java.util.Scanner;
import javax.swing.JTextArea;
/**
* My RNG game has multiple choices; Array, Coins, and colors.
*/
public class RandomNumberGenerator
{
// all colors available
private static final int COLOR_MAX = 256;
private static int RED, GREEN, BLUE;
private static int MY_RANDOM;
static Scanner MY_CONSOLE = new Scanner(System.in);
static Random RANDOM_NUMBER = new Random();
private static int[] RANDOM_NUM_ARRAY;
/**
* Make the game work! Main System of the game.
*/
public static void main(String[] args)
{
while (true)
{
// menu intro
System.out.println("Welcome to the Random Generation Game!");
System.out.println("Chose an option below: ");
System.out.println();
// menu
System.out.println("1. Generate a random array of numbers!");
System.out.println("2. Flip a coin!");
System.out.println("3. Create a random color!");
System.out.println("4. Exit!");
int option = MY_CONSOLE.nextInt();
// which option is chosen?
// random array game
if (option == 1)
{
createYourRandomArray();
}
// coin game
else if (option == 2)
{
flipTheCoinGame();
}
// color game
else if (option == 3)
{
getARandomColor();
}
// quit?
// I tried to put 1, 2, 3 and 4 into constants but then the code
// would not read the value behind the constant and would go into
// my else...
else if (option == 4)
{
break;
}
// Error!
else
{
System.out.println("Invalid! Choose 1-4!");
}
}
// close console
MY_CONSOLE.close();
System.out.println();
// end of game text
System.out.println("See ya later!");
}
// random array game works
/**
* The array of random numbers created here.
*/
public static void createYourRandomArray()
{
// elements?
System.out.println("How many elements do you want in your array?");
int element = MY_CONSOLE.nextInt();
MY_CONSOLE.nextLine();
// min?
System.out.println("Min value?");
int myMin = MY_CONSOLE.nextInt();
MY_CONSOLE.nextLine();
// max?
System.out.println("Max?");
int myMax = MY_CONSOLE.nextInt();
MY_CONSOLE.nextLine();
// random works
RANDOM_NUM_ARRAY = new int[element];
// open
System.out.println();
System.out.print("[");
//
for (int i = 0; i < RANDOM_NUM_ARRAY.length; i++)
{
MY_RANDOM = RANDOM_NUMBER.nextInt(myMax - myMin + 1);
MY_RANDOM += myMin;
RANDOM_NUM_ARRAY[i]++;
RANDOM_NUM_ARRAY[i] = MY_RANDOM;
if (i < RANDOM_NUM_ARRAY.length - 1)
{
System.out.print(RANDOM_NUM_ARRAY[i] + ", ");
}
else
{
System.out.print(RANDOM_NUM_ARRAY[i]);
}
}
System.out.println("]");
System.out.println();
}
/**
* The Flip coin part of game created here.
*/
public static void flipTheCoinGame()
{
int coinTail = 0;
int coinHead = 0;
System.out.println("How many times would you like to flip the coin?");
int youFlip = MY_CONSOLE.nextInt();
System.out.println();
for (int i = 0; i < youFlip; i++)
{
MY_RANDOM = RANDOM_NUMBER.nextInt(2);
if (MY_RANDOM == 1)
{
System.out.print("heads, ");
coinHead++;
}
// if not heads then tails
else
{
System.out.print("tails, ");
coinTail++;
}
}
System.out.println();
System.out.println("You flipped " + coinHead + " heads and " + coinTail
+ " tails!");
System.out.println();
}
// Generates color in RGB form.
/**
* Random color generator. Creates a random RGB.
*/
public static void getARandomColor()
{
System.out.println();
System.out.println("Your random color is...");
// red
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
RED = MY_RANDOM;
// green
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
GREEN = MY_RANDOM;
// blue
MY_RANDOM = RANDOM_NUMBER.nextInt(COLOR_MAX);
BLUE = MY_RANDOM;
// combinations...
System.out.println("Your color is r: " + RED + ", g: " + GREEN
+ ", b: " + BLUE + "!");
System.out.println();
}
}
解决方案
I think there in no method to get name of color in java. so you create the following method.
String getColorName(int r, int g, int b){switch(r){case 0: switch(g){
case 0: switch(b)
{
case 0: return "black";
break;
case 128: return "Navy";
break;
case 255: return "Blue";
break;
//continue for all color
}
}
}
you can refer this for color names and RGB values. enter link description here
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