Extjs4组合框中的displayValue [英] Extjs4 combobox displayValue in grid

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本文介绍了Extjs4组合框中的displayValue的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

请帮忙。
我想在网格中显示我的 displayValue
我在这里找到了解决方案,但我不明白如何使用它。我的代码:

 列:[...,{
header:'Product',
id :'combo',
locked:true,
dataIndex:'prod_id',
editor:{
xtype:'combobox',
store:new Ext.data .Store({
fields:['value','display'],
data:prod_list
}),
displayField:'display',
valueField: 'value'
}
},...]



h2>

  Ext.util.Format.comboRenderer = function(combo){
return function(value){
var record = combo.findRecord(combo.valueField || combo.displayField,value);
返回记录? record.get(combo.displayField):combo.valueNotFoundText;
}
}

{
header:'Товар',
id:'combo',
locked:true,
dataIndex:'prod_id',
编辑器:MyEditor,
renderer:Ext.util.Format.comboRenderer(MyEditor)
}
  p $ p> 

var MyEditor = new Ext.form.field.ComboBox({
store:new Ext.data.Store({
fields:['value','display'],
data:prod_list
}),
displayField:'display',
valueField:'value'
});



一切正常,但我无法编辑。问题是什么?



对我的英语很抱歉。

解决方案

  var myStore = new Ext.data.Store({
fields:['value','display'],
data:prod_list
});

...

 编辑器:{
xtype:'combobox',
store:myStore,
displayField:'display',
valueField:'value'
},
renderer:function(val){
index = myStore.findExact('value',val);
if(index!= -1){
rs = myStore.getAt(index).data;
return rs.display;
}
}


Please, help. I want to show my displayValue in the Grid. I found the solution here, but I can't understand how use it. My code:

columns:[...,{
    header: 'Product',
    id: 'combo',
    locked: true,
    dataIndex: 'prod_id',
    editor: {
        xtype: 'combobox',
        store: new Ext.data.Store({
            fields: ['value','display'],
            data: prod_list
    }),
    displayField: 'display',
    valueField: 'value'
    }
},...]

Solution

Ext.util.Format.comboRenderer = function(combo){
    return function(value){
    var record = combo.findRecord(combo.valueField || combo.displayField, value);
        return record ? record.get(combo.displayField) : combo.valueNotFoundText;
    }
}

{
    header: 'Товар',
    id: 'combo',
    locked: true,
    dataIndex: 'prod_id',
    editor: MyEditor,
    renderer: Ext.util.Format.comboRenderer(MyEditor)
}

I tried to define editor outside of the column array.

    var MyEditor = new Ext.form.field.ComboBox({
        store: new Ext.data.Store({
            fields: ['value','display'],
            data: prod_list
        }),
        displayField: 'display',
        valueField: 'value'
    });

And all is fine, but I can't edit it. What is the problem?

Sorry for my English.

解决方案

var myStore = new Ext.data.Store({
    fields: ['value','display'],
    data: prod_list
});

...

            editor: {
                xtype: 'combobox',
                store: myStore,
                displayField: 'display',
                valueField: 'value'
            },
            renderer: function(val){
                index = myStore.findExact('value',val); 
                if (index != -1){
                    rs = myStore.getAt(index).data; 
                    return rs.display; 
                }
            }

这篇关于Extjs4组合框中的displayValue的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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