如何在Swift中访问程序参数？ [英] How do I access program arguments in Swift?

问题描述

C和衍生产品 argc 和 argv （和 envp ）参数到它们的入口点函数，但Swift没有一个适当的：顶级代码只是代码，它没有参数。

C and derivatives have argc and argv (and envp) parameters to their entry point functions, but Swift doesn't have one proper: top-level code is just code and it doesn't have parameters.

可以在Swift程序中访问等效的 argc 和 argv ？

How can one access the equivalent of argc and argv in a Swift program?

推荐答案

作为参考（自Swift 3.0 August 4快照以来）：

Process 刚刚重命名为 CommandLine

For reference (since Swift 3.0 August 4 snapshot):
Process was just renamed into CommandLine

let arguments = CommandLine.arguments

（由于某种原因，这未在 changelog ）

(for some reason this wasn't mentioned on the changelog)

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