如何在java中执行命令行.exe文件 [英] how to execute command line .exe file in java

问题描述

1. 我想使用java程序将avi文件转换为3gp
   。


2. 为此，我使用EM总计
   视频转换器命令行2.43
   ，命令为
   
   C：\EM
   TVCC> TVCC -f E：\TestVideo\01。 avi -o
   E：\OutputFiles\target.3gp


3. 我有一个程序来执行命令
   在线exe文件< a href =http://www.rgagnon.com/javadetails/java-0014.html =nofollow noreferrer> http://www.rgagnon.com/javadetails/java-0014.html 这是：

其中包含空格的路径 $ b

您可以包括要执行的程序的路径。在Win plateform上，如果路径包含空格，则需要将引号括起来。

  public class Test {
 public static void main（String [] args）throws Exception {
 Process p = Runtime.getRuntime（）。exec（
\c：/ program files / windows / notepad.exe\）; 
 p.waitFor（）; 
} 
} 
  

如果您需要传递参数，字符串数组，特别是如果它们包含空格。

  String [] cmd = {myProgram.exe，-o =这是一个选项}; 
 Runtime.getRuntime（）。exec（cmd）; 
  

如果使用start命令，要启动的文件的路径包含空格，开始命令的标题。

  String fileName =c：\\Applications\\My Documents \\test.doc; 
 String [] commands = {cmd，/ c，start，\DummyTitle\，fileName}; 
 Runtime.getRuntime（）。exec（commands）; 
  

***任何人都可以帮我把上面的命令放在这段代码中？ 。

这是我使用的确切的java代码：

public class Test {
public static void main（String [] args）throws Exception {

String [] cmd = {C：\\Program Files \\EM TVCC\\TVCC.exe，-f C：\\Program Files\\EM TVCC\\01.avi ，-o C：\\Program Files\\EM TVCC\\target.3gp};
Process p = Runtime.getRuntime（）。exec（cmd）;
p.waitFor（）;
}
}


解决方案

你的问题中有所有的部分。

如下所示应该可以工作：

  public class Test {
 public static void main（String [] args）throws Exception {
 
 String [] cmd = {C：\\EM TVCC\\TVCC.exe，-f E：\\TestVideo\\01.avi，-o E：\\OutputFiles\\ target.3gp}; 
 Process p = Runtime.getRuntime（）。exec（cmd）; 
 p.waitFor（）; 
} 
} 
  

也就是说，一个好主意，你应该从某个地方读他们;您的程序的参数，属性文件等。

1. i want to convert an avi file to 3gp using java program.
2. For this i am using "E.M. Total Video Converter Command Line 2.43" and the command for it is
   "C:\E.M. TVCC>TVCC -f E:\TestVideo\01.avi -o E:\OutputFiles\target.3gp"
3. I got a program to execute command line exe file on site http://www.rgagnon.com/javadetails/java-0014.html which is:

Path to executable with spaces in them

You can include a path for the program to be executed. On the Win plateform, you need to put the path in quotes if the path contains spaces.

public class Test {
  public static void main(String[] args) throws Exception {
    Process p = Runtime.getRuntime().exec(
       "\"c:/program files/windows/notepad.exe\"");
    p.waitFor();
  }
}

If you need to pass arguments, it's safer to a String array especially if they contain spaces.

String[] cmd = { "myProgram.exe", "-o=This is an option" };
Runtime.getRuntime().exec(cmd);

If using the start command and the path of the file to be started contains a space then you must specified a title to the start command.

String fileName = "c:\\Applications\\My Documents\\test.doc";
String[] commands = {"cmd", "/c", "start", "\"DummyTitle\"",fileName};
Runtime.getRuntime().exec(commands);

***Can anyone help me to put the above command in this code?***I dont know the syntax rules to put that command in the above code.Please help me.

This is the exact java code i am using:

public class Test {
    public static void main(String[] args) throws Exception {

        String[] cmd = { "C:\\Program Files\\E.M. TVCC\\TVCC.exe", "-f C:\\Program Files\\E.M. TVCC\\01.avi", "-o C:\\Program Files\\E.M. TVCC\\target.3gp" };
        Process p = Runtime.getRuntime().exec(cmd);
        p.waitFor();
    }
}

解决方案

You've got all the pieces in your question. It's just a matter of putting it all together.

Something such as the following should work:

public class Test {
    public static void main(String[] args) throws Exception {

        String[] cmd = { "C:\\E.M. TVCC\\TVCC.exe", "-f E:\\TestVideo\\01.avi", "-o E:\\OutputFiles\\target.3gp" };
        Process p = Runtime.getRuntime().exec(cmd);
        p.waitFor();
    }
}

That said, hard coding paths like this isn't a good idea, you should read them from somewhere; arguments to your program, a properties file, etc.

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