命令行以递归方式删除匹配的文件和目录 [英] Command line to delete matching files and directories recursively

问题描述

如何递归删除所有档案&匹配某个模式的目录？例如

How can I recursively delete all files & directories that match a certain pattern? e.g. remove all the ".svn" directories and the files they contain?

（仅限于DOS）

推荐答案

因为你正在寻找DOS解决方案，上周的帖子几乎是一样的，一致的是：

Since you're looking for a DOS solution, last week's post was almost identical and the consensus was:

命令行工具删除文件夹在Windows中递归指定的名称？

代表/ d / r。 ％d在（.svn）do @if存在
％drd / s / q％d

for /d /r . %d in (.svn) do @if exist "%d" rd /s/q "%d"

或

代表/ fusebackq％d in（dir .svn
/ ad / b / s） do rd / s / q％d

for /f "usebackq" %d in ("dir .svn /ad/b/s") do rd /s/q "%d"

实际上，SVN还提供导出工作目录的选项， / _svn目录。

Actually, SVN also gives you the option to export a working directory without the .svn/_svn directories.

后来，三年后：
我认为人们最终需要递归删除.svn / _svn文件夹的原因是因为他们' ve直接复制他们的本地工作副本到一个新的位置，以便做一个文件夹比较他们的修改版本相比，一个干净的出口，即一些东西变得与修改后的本地工作副本。 （至少这就是为什么我需要它。它是绝对更容易/更快地只使用'svn导出'，当可能的时候。）

Afterthoughts, three years later: I think the reason people end up needing to recursively delete the .svn/_svn folders is because they've directly copied their local working copy to a new location in order to do a folder comparison of their modified version compared to a clean export, i.e. after something goes awry with the modified local working copy. (At least that's why I've needed it. It's definitely easier/faster to just use 'svn export' when that's possible.)

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