C＃INT为byte [] [英] C# int to byte[]

问题描述

如果我需要转换的 INT 到字节[] 所以我可以使用 BitConverter.GetBytes（）。但如果我应遵循这样的：

If I need to convert an int to a byte[] so I could use BitConverter.GetBytes(). But if I should follow this:

有符号整数的XDR是一个32位数据的连接codeS中的一个整数      范围[-2147483648,2147483647]。该整数再presented在      二进制补码。最多和最少的显著字节      0和3，分别整数声明如下：

An XDR signed integer is a 32-bit datum that encodes an integer in the range [-2147483648,2147483647]. The integer is represented in two's complement notation. The most and least significant bytes are 0 and 3, respectively. Integers are declared as follows:

来源：RFC1014 3.2

Source: RFC1014 3.2

用什么方法，我应该用那么有没有办法做到这一点？它如何看，如果你写你自己的呢？

What method should I use then if there is no method to do this? How would it look like if you write your own?

我不明白的文字100％，所以我不能在我自己实现它。

I don't understand the text 100% so I can't implement it on my own.

推荐答案

该RFC只是想说，有符号整数是一个正常的4字节的整数，下令在大端方式字节。

The RFC is just trying to say that a signed integer is a normal 4-byte integer with bytes ordered in a big-endian way.

现在，你是最有可能工作一小端机器上 BitConverter.GetBytes（）会给你的字节[] 逆转。所以，你可以尝试：

Now, you are most probably working on a little-endian machine and BitConverter.GetBytes() will give you the byte[] reversed. So you could try:

int intValue;
byte[] intBytes = BitConverter.GetBytes(intValue);
Array.Reverse(intBytes);
byte[] result = intBytes;

对于code是最轻便的，但是，你可以做到这一点是这样的：

For the code to be most portable, however, you can do it like this:

int intValue;
byte[] intBytes = BitConverter.GetBytes(intValue);
if (BitConverter.IsLittleEndian)
    Array.Reverse(intBytes);
byte[] result = intBytes;

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