如何更新命令行输出? [英] How to update command line output?
问题描述
在Linux中, stdout
到命令行,我想更新特定区域,例如 apt-get
输出:
54%[等待头文件] [等待头文件] 211 kB / s 3s
, kB / s
如果我们使用 printf
,那么我们将得到多行输出。我试过下面的 printf
:
printf(\e [ 1; 1H \e [2J);
但它会清除所有输出。
解决方案使用回车。它会将光标移回到行的开头,从中可以覆盖之前的行。例如:
printf(Hello,world!\rX);
将显示为:
Xello,world!
请务必经常刷新 stdout
希望它可见:
fflush(stdout);
In Linux, While stdout
to command line, I want to update specific area, such as the apt-get
output:
54% [Waiting for headers] [Waiting for headers] 211 kB/s 3s
the percentage, kB/s and second will update each second.
If we use printf
then we will get multiple lines output them. I have tried following printf
:
printf("\e[1;1H\e[2J");
But it cleans all the output.
My question is how to update specific area and keep others stable?
解决方案 Use the carriage return. It will move the cursor back to the start of the line, from which you can overwrite what was in the line before. For example:
printf("Hello, world!\rX");
Will be visible as:
Xello, world!
Make sure you flush stdout
often if you want it to be visible:
fflush(stdout);
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