Java Comparator给出了要比较的属性的名称 [英] Java Comparator given the name of the property to compare

问题描述

我的问题是这个;我必须订购一个数据表。表的每一行都是一个存储在List中的对象（我们称之为TableObject）。每一列数据都是类的属性（通常是String）。

My problem is this; I have to order a table of data. Each row of the table is an object (lets call it TableObject) stored in a List. Each column of data is a property of the class (usually a String).

当用户点击任何列时，我必须执行典型的数据排序。所以我想到将列表更改为TreeSet并在我的TableObject中实现Comparator。

I have to do the typical ordering of data when the user clicks on any column. So I thought about changing the List to a TreeSet and implementing Comparator in my TableObject.

问题出现在我尝试重新排序TreeSet时。首先比较是很容易的（parseInt中的异常的cheeking已被省略）：

The problem comes when I try to reorder the TreeSet. The compare is fairly easy at first (cheeking for exceptions in parseInt have been omitted):

   public int compare(TableObject to1, TableObject to2){
        TableObject t1 = to1;
        TableObject t2 = to2;

        int result = 1;

        if(Integer.parseInt(t1.getId()) == Integer.parseInt(t2.getId())){result=0;}
        if(Integer.parseInt(t1.getId()) < Integer.parseInt(t2.getId())){result=-1;}

        return result;

    }

但是当我必须重新排序数据文本或者通过其他几十个数据，TableObject有我有一个问题。
我不想创建几十个比较函数，每个为一个。我不喜欢使用开关（或一连串的ifs）来决定如何比较对象。

But when I have to reorder by the text of the data or by other dozens of data that the TableObject has I have a problem. I do not want to create dozens of compare functions, each for one. I prefer not to use a switch (or a chain of ifs) to decide how to compare the object.

有什么办法以某种方式做这个），这不意味着我会写几百行几乎相同的代码？

Is there any way to do this in some way (like Reflexive), that doesn't imply that I will write like hundreds of lines of nearly the same code?

感谢所有！

推荐答案

Bean比较器应该工作。

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