[] ==！[]计算结果为true [英] [] == ![] evaluates to true

问题描述

我想知道为什么标题中给出的表达式

I would liketo know why the expression given in the title

[] ==！[]

被计算为true。

不能将数组作为字符串进行比较。我明白了。如果

You cannot compare arrays as strings. I get that. If

[] == []

将评估为false，因为引用不同。虽然如果我们有以下语句。

will evaluate to false because the references are different. Though if we have the following statement.

var arr = []; 
arr == arr // this evaluates to true simply because references are the same.

按顺序A == B返回true A和B必须为false或true。
A ==！B为了返回真A可以是真的，B可以是假或反之亦然，但在这种情况下A和B是相同的值，所以我不能得到它。

In order A == B to return true either A and B have to be false or true. A == !B in order to return true A can be true and B can be false or vice versa but in this case A and B are the same values so I don't get it.

推荐答案

！[] 计算为 false 因为引用是真的。 [] 可以转换为falsey的数字（在这种情况下为0）。因此：条件通过相等。如果你 === 它会是false。

![] evaluates to false because the reference is truthy. [] can be converted to an number (0 in this case) which is falsey. Therefore: the condition passes as equal. If you did === it would be false.

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