检查字符串是否由与另一个字符串相同的字母构建 [英] Check if a string is build out of the same letters as another string

问题描述

这个主题很好地解释了我的想法。所以我想达到的是：

The topic explains my wish pretty well i think. So what i want to reach is:

madeOutOfSameLetters("aaasdf", "xyz") // false
madeOutOfSameLetters("aaasdf", "asdf") // false
madeOutOfSameLetters("aaasdf", "aaasdd") // false
madeOutOfSameLetters("aaasdf", "fdsaaa") // true

是否有我可以使用的（组合）方法，或者我需要通过我的

Is there a (combination of) method(s) I can use for, or do I need to do it by my own?

在第二种情况下，我会计算两个字符串的每个字母，将它们写入数组并将它们相互比较。但这似乎比它更复杂，对我来说。

In second case I would count each letter of both strings, write it into arrays and compare them to each other. But that seems to be more complicated than it has to be to me. Any easier ideas?

推荐答案

您可以使用 String.toCharArray（） 和Arrays.sort(char[]) 和 Arrays.equals（char []，char []） 。也就是说，类似

You could use String.toCharArray() and Arrays.sort(char[]) and Arrays.equals(char[], char[]). That is, something like,

public static boolean madeOutOfSameLetters(String a, String b) {
    if (a == null) {
        return b == null;
    } else if (b == null) {
        return false;
    }
    char[] left = a.toCharArray();
    char[] right = b.toCharArray();
    Arrays.sort(left);
    Arrays.sort(right);
    return Arrays.equals(left, right);
}

public static void main(String[] args) throws Exception {
    System.out.println(madeOutOfSameLetters("aaasdf", "xyz")); // false
    System.out.println(madeOutOfSameLetters("aaasdf", "asdf")); // false
    System.out.println(madeOutOfSameLetters("aaasdf", "aaasdd")); // false
    System.out.println(madeOutOfSameLetters("aaasdf", "fdsaaa"));// true
}

输出是请求的

false
false
false
true

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