将两个字典与列表类型值进行比较 [英] comparing two dictionaries with list type values

问题描述

我想比较两个字典。我的方法是将它们变成两个单独的元组列表，然后使用set模块。这是一个例证：

I'm trying to compare two dictionaries. My approach is to turn them into two separate lists of tuples and to then use the set module. Here is an illustration:

dict = {'red':[1,2,3],'blue':[2,3,4],'green':[3,4,5]}

dict1 = {'green':[3,4,5],'yellow':[2,3,4],'red':[5,2,6]}

intersection = set(set(dict.items()) & set(dict1.items()))

显然，这是比较两个元组的列表，python不喜欢。我得到一个TypeError：'list'是不可缓解的错误（或类似的措辞）。

apparently, this is comparing two lists of tuples and python doesn't like that. I get a TypeError: 'list' is unhashable error (or similar wording).

我想交集包含 [（'green' [3,4,5]）] 。任何想法？

I would like intersection to contain [('green',[3,4,5])]. Any ideas?

推荐答案

shared_keyvals = dict( (key, dict1[key])
                       for key in (set(dict1) & set(dict2))
                       if dict1[key] == dict2[key]
                     )

你甚至可以将它变成一个函数：

You can even make this into a function:

def shared_keyvals(dict1, dict2):
    return dict( (key, dict1[key])
                 for key in (set(dict1) & set(dict2))
                 if dict1[key] == dict2[key]
               )

显然，如果你不喜欢以字典形式输出，你可以删除 dict（）调用并用列表解析括号（ [] ）。

Obviously, if you prefer to not have the output in dictionary form, you can just remove the dict() call and replace with with list comprehension brackets ([]) instead.

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