Java压缩字符串 [英] Java compressing Strings
问题描述
我需要创建一个接收String并返回String的方法。
I need to create a method that receives a String and also returns a String.
Ex输入:AAABBBBCC
Ex input: AAABBBBCC
Ex输出:3A4B2C
Ex output: 3A4B2C
好吧,这是相当尴尬,我不能在接受采访,我今天(我申请一个初级职位),现在,在家里尝试做一个工作,静态,我的意思,不使用循环,这是一种无用的,但我不知道,如果我没有得到足够的睡眠时间或东西,但我不能弄清楚我的for循环应该是什么样子。这是代码:
Well, this is quite embarrassing and I couldn't manage to do it on the interview that I had today ( I was applying for a Junior position ), now, trying at home I made something that works statically, I mean, not using a loop which is kind of useless but I don't know if I'm not getting enough hours of sleep or something but I can't figure it out how my for loop should look like. This is the code:
public static String Comprimir(String texto){
StringBuilder objString = new StringBuilder();
int count;
char match;
count = texto.substring(texto.indexOf(texto.charAt(1)), texto.lastIndexOf(texto.charAt(1))).length()+1;
match = texto.charAt(1);
objString.append(count);
objString.append(match);
return objString.toString();
}
感谢您的帮助,我正在努力提高我的逻辑技能。 / p>
Thanks for your help, I'm trying to improve my logic skills.
推荐答案
循环通过字符串记住你最后看到的。每次你看到相同的字母数。当你看到一个新信件,你把你的计数到输出,并设置新的信函作为你最后一次看到。
Loop through the string remembering what you last saw. Every time you see the same letter count. When you see a new letter put what you have counted onto the output and set the new letter as what you have last seen.
String input = "AAABBBBCC";
int count = 1;
char last = input.charAt(0);
StringBuilder output = new StringBuilder();
for(int i = 1; i < input.length(); i++){
if(input.charAt(i) == last){
count++;
}else{
if(count > 1){
output.append(""+count+last);
}else{
output.append(last);
}
count = 1;
last = input.charAt(i);
}
}
if(count > 1){
output.append(""+count+last);
}else{
output.append(last);
}
System.out.println(output.toString());
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