是否有任何java压缩实用程序 [英] Is there any java compression utility
问题描述
我需要(解压缩)一些文件,一些谷歌后,我还没有找到任何实用程序。我知道我可以做它与内置的java.uitl.zip。*类,但没有任何实用程序,这将使它更容易,最好是这样:
I need to (un)zip some files and after some googling I haven't found any utility for doing it. I know I can do it with built-in java.uitl.zip.* classes but isn't there any utility, that will make it easer, best like this:
SomeClass.unzip(file_name.zip,target_directory);
SomeClass.unzip("file_name.zip", "target_directory");
或
SomeClass.zip (source_directory,target_file_name.zip,递归);
SomeClass.zip("source_directory", "target_file_name.zip", recursively);
我不想处理流。只是文件,或更好只是文件名...
I don't want to handle streams. Just file, or better just file names...
推荐答案
Deflater / Inflater 类://stackoverflow.com/questions/127001/whats-a-good-compression-library-for-java>什么是Java的好压缩库?。
How about the Deflater/Inflater classes mentioned in the question "What’s a good compression library for Java?".
我知道Java提出的当前接口是基于流的,而不是文件名,但是根据 Java压缩,很容易构建一个这样的实用程序类:
I know the current interfaces proposed by Java are Stream-based, not "filename"-based, but according to the following article on Java compression, it is easy enough to build an utility class around that:
基于文件名的解压缩函数将如下所示:
For instance, a Unzip function based on a filename would look like:
import java.io.*;
import java.util.zip.*;
public class UnZip {
final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedOutputStream dest = null;
FileInputStream fis = new
FileInputStream(argv[0]);
ZipInputStream zis = new
ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null) {
System.out.println("Extracting: " +entry);
int count;
byte data[] = new byte[BUFFER];
// write the files to the disk
FileOutputStream fos = new
FileOutputStream(entry.getName());
dest = new
BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))
!= -1) {
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
zis.close();
} catch(Exception e) {
e.printStackTrace();
}
}
}
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