console.log对象处于当前状态 [英] console.log object at current state
问题描述
console.log
将显示处于最后执行状态的对象,而不是显示 console.log
被调用。
我必须克隆对象,只是通过 console.log
如何更改console.log的默认行为? (
)
var test = {a:true}
console.log(test); // {a:false}
test.a = false;
console.log(test); // {a:false}
找到 console.dir()
。
console.log code>不会做你想要的,因为它打印一个对象的引用,当你弹出它打开,它的改变。
console.dir
在调用对象时打印对象中属性的目录。
JSON构思下面是一个好的;你甚至可以继续解析JSON字符串,并得到一个可浏览的对象,如.dir()会给你:
console.log JSON.parse(JSON.stringify(obj)));
console.log
will show the object at the last state of execution, not at the state when console.log
was called.
I have to clone the object just to output it via console.log
to get the state of the object at that line.
How can I change the default behavior of console.log? (Error console in safari, no add-on)
Example:
var test = {a: true}
console.log(test); // {a: false}
test.a = false;
console.log(test); // {a: false}
I think you're looking for console.dir()
.
console.log()
doesn't do what you want because it prints a reference to the object, and by the time you pop it open, it's changed. console.dir
prints a directory of the properties in the object at the time you call it.
The JSON idea below is a good one; you could even go on to parse the JSON string and get a browsable object like what .dir() would give you:
console.log(JSON.parse(JSON.stringify(obj)));
这篇关于console.log对象处于当前状态的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!