在Java中构建一个复制构造函数 [英] Building a copy constructor in Java
问题描述
如何构建接收另一个点(x,y)并复制其值的复制构造函数?
How do I build a copy constructor that receive another point (x,y) and copy its values ?
我决定签名: public Point1(Point1 other)
,但我不知道该写什么...
I decide a signature: public Point1 (Point1 other)
, but I don't know what to write in it...
Point类看起来像: / p>
The Point class looks like:
public class Point1
{
private int _x , _y;
public Point1 (Point1 other)
{
...
...
}
//other more constructors here...
}
我试过: b
$ b
I tried:
public Point1 (Point1 other)
{
_x = other._x ;
_y = other._y;
}
但我几乎肯定我可以做得更好..
But I almost sure I can do it better..
thnx
推荐答案
不,你的尝试
public Point1(Point1 other)
{
_x = other._x ;
_y = other._y;
}
是绝对精细...(我已更正参数类型。
is absolutely fine... (I've corrected the parameter type.)
我会试着让 _x
和 _y
final,并使类最终,但这是因为我喜欢不变的类型。其他人肯定有不同的意见:)
I'd be tempted to make _x
and _y
final, and make the class final, but that's because I like immutable types. Others definitely have different opinions :)
在继承层次结构上克隆有点棘手 - 层次结构中的每个类都必须有一个相关的构造函数,将任何参数传递给超类构造函数,然后只复制其自己的字段。例如:
Cloning on an inheritance hierarchy is slightly trickier - each class in the hierarchy has to have a relevant constructor, pass whatever argument it's given to the superclass constructor, and then copy just its own fields. For example:
public class Point2 extends Point1
{
private int _z;
public Point2(Point2 other)
{
super(other);
this._z = other._z;
}
}
这在实现方面并不糟糕,您想要忠实克隆 Point2
,您需要知道是 Point2
调用正确的构造函数。
That's not too bad on the implementation side, but if you want to faithfully clone a Point2
you need to know it's a Point2
in order to call the right constructor.
实现可克隆
允许这样做更简单一点,考虑周围...基本上克隆对象不是那么简单,它可能会出现:)(我敢肯定有效的Java中有一个条目,如果你没有副本,现在买一个。)
Implementing Cloneable
allows this to be done a bit more simply, but there are other things to consider around that... basically cloning objects isn't as simple as it might appear :) (I'm sure there's an entry in Effective Java for it. If you don't have a copy, buy one now.)
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