如何解释构造函数中的return语句? [英] how to explain return statement within constructor?
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问题描述
据我所知,构造函数返回无,甚至无void,
以及
return;任何方法中的
意味着返回void。
所以在我的程序
public class returnTest {
public static void main args){
returnTest obj = new returnTest();
System.out.println(here1);
}
public returnTest()
{
System.out.println(here2);
return;
}
}
我正在呼叫
return;
这将返回VOID,但是构造函数不应该返回任何东西,
程序编译正确。
请解释。
解决方案
return
在构造函数中只是跳出构造函数的指定点。
例如
<$ p如果您在某些情况下不需要完全初始化类, $ p>
//一个非常有用的例子...
class Demo
{
protected int id = 0;
protected int count = 0;
public Demo(int id,int count)
{
this.id = id;
this.count = count;
if(this.count< = 0){
return;
}
// count> 0,做一些有意义的事情
as far as i know , the constructor return nothing , not even void ,
and also
return ;
inside any method means to return void .
so in my program
public class returnTest {
public static void main(String[] args) {
returnTest obj = new returnTest();
System.out.println("here1");
}
public returnTest ()
{
System.out.println("here2");
return ;
}
}
i am calling
return;
which will be returning VOID , but constructor is not supposed to return anything , the program compiles just fine .
please explain .
解决方案
return
in a constructor just jumps out of the constructor at the specified point. You might use it if you don't need to fully initialize the class in some circumstances.
e.g.
// A very contrived example...
class Demo
{
protected int id = 0;
protected int count = 0;
public Demo(int id, int count)
{
this.id = id;
this.count = count;
if (this.count <= 0) {
return;
}
// count > 0, do something meaningful
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