PHP：如何将子类__construct（）参数传递给parent :: __ construct（）？ [英] PHP: How to Pass child class __construct() arguments to parent::__construct()?

问题描述

我在PHP中有一个类如下：

I have a class in PHP like so:

class ParentClass {
    function __construct($arg) {
        // Initialize a/some variable(s) based on $arg
    }
}

它有一个子类，如下：

class ChildClass extends ParentClass {
    function __construct($arg) {
        // Let the parent handle construction. 
        parent::__construct($arg); 
    }
}

如果由于某种原因，ParentClass需要更改要采用多个可选参数，我想让我的Child类提供只是为了？除非我重新编码ChildClass，它只会接受构造函数的一个参数，并且只会传递那个参数。

What if, for some reason, the ParentClass needs to change to take more than one optional argument, which I would like my Child class to provide "just in case"? Unless I re-code the ChildClass, it will only ever take the one argument to the constructor, and will only ever pass that one argument.

这是如此罕见或这样一个糟糕的做法，通常的情况是，一个ChildClass不需要继承自一个ParentClass，接受不同的参数？

Is this so rare or such a bad practice that the usual case is that a ChildClass wouldn't need to be inheriting from a ParentClass that takes different arguments?

基本上，我已经在Python中看到，你可以通过 somefunction（* args）将一个可能未知数的参数传递给函数。 code>其中'args'是某种数组/ iterable。 PHP中存在类似的东西吗？或者我应该重构这些类，然后再继续吗？

Essentially, I've seen in Python where you can pass a potentially unknown number of arguments to a function via somefunction(*args) where 'args' is an array/iterable of some kind. Does something like this exist in PHP? Or should I refactor these classes before proceeding?

推荐答案

在php中有这样的东西，虽然有点冗长：

There is something like this in php, though a bit verbose:

$args = func_get_args();
call_user_func_array(array($this, 'parent::__construct'), $args);

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