Java构造函数具有比其类更宽的访问级别 [英] Java constructor having broader access level than its class

问题描述

Java规范允许具有默认访问权限的类具有其构造方法的公共访问权限，它的目的是什么，因为它不能在其包外引用。

Java specification allows a class with default access to have its constructor public access, what is the purpose of it, since it cannot be referenced outside its package?

推荐答案

我想要这个注释，但因为在注释中不允许使用代码标签....

I wanted to make this a comment, but since no code tags are allowed in comments....

on CristopheDs answer：

In regards to your comment on CristopheDs answer:

package bob;

class MySuperHiddenClass {

  public MySuperHiddenClass() {
        System.out.println("bob");
  }
}

和

package bob;
public class MyPublicClass extends MySuperHiddenClass {

}

在MyPublicClass中声明，但您仍然可以从任何包调用新的MyPublicClass。

No constructor was declared in MyPublicClass, but you can still call new MyPublicClass from any package.

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