显示准确的结果 [英] displaying accurate results
问题描述
我正在为我的移动网站创建网站目录（此处）
I'm creating a web site directory for my mobile site (FOUND HERE)
我想出了如何从我的表promo_cat列表显示从我的mysql表到我的主页的列表。
I have figured out how to display listings from my mysql table to my home page from my tables promo_cat list.
遇到麻烦的事情是这样的：
The thing im having trouble with is this:
一旦点击了它的一个catagories我的list.php页面。
once clicking on one of the catagories it leads me to my list.php page.
如何让此网页显示与点击类别而非其他类别相关的结果？
How do I get this page to display results related to the category clicked and not others?
：点击免费时出现此页： http：//www.xclo .mobi / xclo2 / list.php？id =免费。其中显示所有结果。它应该只显示具有promo_cat字段为FREE的结果，并且不应显示任何其他结果，因为它目前。
For example:when clicking on "FREE" brings up this page: http://www.xclo.mobi/xclo2/list.php?id=FREE. Which displays all results. it should only display results that have a promo_cat field as "FREE" and should not display any other results as it does currently.
我的list.php代码：
<?php
include_once('include/connection.php');
include_once('include/article.php');
$article = new article;
$articles = $article->fetch_all();
?>
<html>
<head>
<title>xclo mobi</title>
<link rel="stylesheet" href="other.css" />
</head>
<body>
<?php include_once('header.html'); ?>
<div class="container">
<a href="index.php" id="logo">Category = ???</a>
<ol>
<?php foreach ($articles as $article) { ?>
<div class="border">
<a href="single.php?id=<?php echo $article['promo_title']; ?>" style="text-decoration: none">
<img src="<?php echo $article['promo_image']; ?>" border="0" class="img" align="left"><br />
<a href="<?php echo $data['promo_link']; ?>" target="_blank"><img alt="" title="" src="GO.png" height="50" width="50" align="right" /></a>
<font class="title"><em><center><?php echo $article['promo_title']; ?></center></em></font>
<br /><br />
<font class="content"><em><center><?php echo $article['promo_content']; ?></center></em></font>
</div><br/><br />
</a>
<?php } ?>
</ol>
</div>
</body>
</html>
/include/article.php
<?php
class article {
public function fetch_all(){
global $pdo;
$query = $pdo->prepare("SELECT * FROM mobi");
$query->execute();
return $query->fetchAll();
}
public function fetch_data($promo_title) {
global $pdo;
$query = $pdo->prepare("SELECT * FROM mobi WHERE promo_title = ?");
$query->bindValue(1, $promo_title);
$query->execute();
return $query->fetch();
}
}
?>
推荐答案
根据您提供的代码， / p>
Based on the code you provided, try this:
<?php foreach ($articles as $article) {
if ($article['promo_cat'] === 'FREE') { ?>
// Keep the rest of the code
//instead of <?php } ?> - put...
<?php } } ?>
请记住，这很乱。但是 foreach 语句（我想象）正在用于打印所有帖子。所以，在打印出一个帖子之前，你只需检查promo_title是否是免费的，GIFT等。如果不是，那么它不打印该项目。
Keep in mind, this is messy. But the foreach statement (I imagine) is being used to print out all posts. So, before printing out a post, you just check to see if the promo_title is FREE, GIFT, etc. If it's not, then it doesn't print that item.
您可以通过传递一个$ _GET变量（您显然正在做，但代码从不使用此变量）与当前促销标题和改变条件行以表示
You can make this more dynamic by passing in a $_GET variable (which you apparently are doing, but the code is never using this variable) with the current promo title and altering the conditional line to say
if（$ article ['promo_cat'] === $ _GET ['id']）
希望有所帮助！
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