无法使用Python登录Amazon [英] Unable to log in to Amazon using Python
问题描述
我使用Python 3编写一个脚本来登录到亚马逊来抓取我的Kindle亮点。本文基于： https://blog.jverkamp.com / 2015/07/02 / scraping-kindle-highlights /
I'm using Python 3 to write a script to log in to Amazon to grab my Kindle highlights. It is based on this article: https://blog.jverkamp.com/2015/07/02/scraping-kindle-highlights/
我无法成功登录，而是收到一条消息， ：
I am unable to successfully log in and instead get a message saying to enable cookies to continue:
<RequestsCookieJar[<Cookie ubid-main=189-4768762-8531647 for .amazon.com/>]>
Failed to login:
Please Enable Cookies to Continue
To continue shopping at Amazon.com, please enable cookies in your Web browser.
Learn more about cookies and how to enable them.
我已经包含了处理cookie的请求会话，但它似乎不工作。
I have included requests sessions to handle cookies, but it doesn't seem to be working.
以下是我使用的代码：
import bs4, requests
session = requests.Session()
session.headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.110 Safari/537.36'
}
# Log in to Amazon, we have to get the real login page to bypass CSRF
print('Logging in...')
response = session.get('https://kindle.amazon.com/login')
soup = bs4.BeautifulSoup(response.text, "html.parser")
signin_data = {}
signin_form = soup.find('form', {'name': 'signIn'})
for field in signin_form.find_all('input'):
try:
signin_data[field['name']] = field['value']
except:
pass
signin_data[u'ap_email'] = 'myemail'
signin_data[u'ap_password'] = 'mypassword'
response = session.post('https://www.amazon.com/ap/signin', data = signin_data)
soup = bs4.BeautifulSoup(response.text, "html.parser")
warning = soup.find('div', {'id': 'message_warning'})
if warning:
print('Failed to login: {0}'.format(warning.text))
我在使用会话时遗漏了什么？
Is there something I'm missing with my use of sessions?
推荐答案
您的登录表单数据实际上不正确，应该是 和
Your signin form data is actually not correct it should be email and password:
signin_data[u'email'] = 'your_email'
signin_data[u'password'] = 'your_password'
您也可以避免使用css select和has_attr尝试：
You can also avoid the try with a css select and has_attr:
import bs4, requests
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.110 Safari/537.36'
}
from bs4 import BeautifulSoup
with requests.Session() as s:
s.headers = headers
r = s.get('https://kindle.amazon.com/login')
soup = BeautifulSoup(r.content, "html.parser")
signin_data = {s["name"]: s["value"]
for s in soup.select("form[name=signIn]")[0].select("input[name]")
if s.has_attr("value")}
signin_data[u'email'] = 'your_em'
signin_data[u'password'] = 'pass'
response = s.post('https://www.amazon.com/ap/signin', data=signin_data)
soup = bs4.BeautifulSoup(response.text, "html.parser")
warning = soup.find('div', {'id': 'message_warning'})
if warning:
print('Failed to login: {0}'.format(warning.text))
print(response.content)
输出的第一行，您可以在结尾看到< title> Amazon Kindle：Home< / title> ：
The first line of the output, you can see <title>Amazon Kindle: Home</title> at the end:
b'<?xml version="1.0" encoding="utf-8"?>\n<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">\n<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-US" lang="en-US">\n <head>\n <title>Amazon Kindle: Home</title>\n
如果它不工作，您应该更新您的请求版本也许尝试另一个用户代理。一旦我改变了 ap_email 和 ap_password ，我就登录了。
If it is not working still, you should update your version of requests and maybe try another user-agent. Once I changed the ap_email and ap_password I logged in fine.
这篇关于无法使用Python登录Amazon的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
