配置grunt copy任务以排除文件/文件夹 [英] Configure grunt copy task to exclude files/folders
问题描述
我安装了grunt任务 grunt-contrib-copy
。我将它嵌入到我的 Gruntfile.js
中并通过 grunt.loadNpmTasks('grunt-contrib-copy');
。
目前我使用以下配置创建一个包含我的js文件/文件夹子集的文件夹。
copy:{
options:{
processContent:[],
processContentExclude:['build / **','bin / **','。 *','* .orig','* .bak','。* / **','* .log','dist / **','test / **','dev / 'pyserver / **','node_modules / **','doc / **']
},
du:{
文件:[
{src: .conf1','.conf2','./config.js'],dest:'output / toolkit /',filter:'isFile'},
{src:['./css/**/ *','./img/**/*','./js/**/*','./release/**/*','./lib/**/*','./ locale / ** / *'],dest:'output / toolkit /'},
{expand:true,cwd:'./',src:['**'],dest:'output / }
]
}
}
每次我运行grunt copy它退出与以下错误消息:
复制Gruntfile.js - > output / Gruntfile.js
警告:处理Gruntfile.js文件时出错。使用--force继续。
我想排除 Gruntfile.js
以及 js / ** / *
中的所有 *。
文件。尝试使用!(。less),!.less,!(*。less),!(./ Grunfile.js),!(* Gruntfile.js)
。 ..但没有什么工作。添加到 processContentExclude
数组,但没有成功。
那么如何排除 Gruntfile.js
和文件夹结构中的所有更少的文件 js / ** / *
?
找不到这些行:
files:[
{src:['.conf1','.conf2','./config.js'],dest:'output / toolkit /',filter:'isFile'},
{src:['./css/**/*','./img/**/*','./js/**/ *','./release/**/*','./lib/**/*','./locale/**/*'],dest:'output / toolkit /'},
{expand:true,cwd:'./',src:['**'],dest:'output /'}
]
因为 {expand:true,cwd:'./',src:['**'],dest:'output /'} code>是一个新的复制步骤,将所有文件从
./
复制到输出
。这对我来说不是必需的,因为上面的行已经将所需的文件复制到 output / toolkit
。
所以下面两行做的工作。不需要选择或任何其他。要阻止 *。less
文件'!** / *。less'
>
files:[
{src:['.conf1','.conf2','config.js'],dest :'output / toolkit /',filter:'isFile'},
{src:['css / **','img / **','js / **','release / ,'lib / **','locale / **','!** / *。less'],dest:'output / toolkit /'}
]
I have installed the grunt task grunt-contrib-copy
. I embedd it in my Gruntfile.js
and load the task via grunt.loadNpmTasks('grunt-contrib-copy');
.
Currently I use following configuration to create a folder with a subset of my js files/folders.
copy: {
options: {
processContent: [],
processContentExclude: ['build/**', 'bin/**', '.*', '*.orig', '*.bak', '.*/**', '*.log', 'dist/**', 'test/**', 'dev/**', 'pyserver/**', 'node_modules/**', 'doc/**']
},
du: {
files: [
{src: ['.conf1', '.conf2', './config.js'], dest: 'output/toolkit/', filter: 'isFile'},
{src: ['./css/**/*', './img/**/*', './js/**/*', './release/**/*', './lib/**/*', './locale/**/*'], dest: 'output/toolkit/'},
{expand: true, cwd: './', src: ['**'], dest: 'output/'}
]
}
}
This works fine, but everytime I run grunt copy it exits with the following error message:
Copying Gruntfile.js -> output/Gruntfile.js
Warning: Error while processing "Gruntfile.js" file. Use --force to continue.
I would like to exclude Gruntfile.js
and all *.less
files in js/**/*
. Tried it with !(.less), !.less, !(*.less), !(./Grunfile.js), !(*Gruntfile.js)
... But nothing works. Added it to the processContentExclude
array, but without success too.
So how can I exclude the Gruntfile.js
and all less files in the folder structure js/**/*
?
Found the solution:
There is no need for these lines:
files: [
{src: ['.conf1', '.conf2', './config.js'], dest: 'output/toolkit/', filter: 'isFile'},
{src: ['./css/**/*', './img/**/*', './js/**/*', './release/**/*', './lib/**/*', './locale/**/*'], dest: 'output/toolkit/'},
{expand: true, cwd: './', src: ['**'], dest: 'output/'}
]
because {expand: true, cwd: './', src: ['**'], dest: 'output/'}
is a new copy step, copying all files from ./
to output
. Which is for me not needed, because the above lines are already copying the required files to output/toolkit
.
So the following two lines does the job. No need for options or anything else. To keep out the *.less
files '!**/*.less'
does the job.
files: [
{src: ['.conf1', '.conf2', 'config.js'], dest: 'output/toolkit/', filter: 'isFile'},
{src: ['css/**', 'img/**', 'js/**', 'release/**', 'lib/**', 'locale/**', '!**/*.less'], dest: 'output/toolkit/'}
]
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