克隆GregorianCalendar的最快方法？ [英] Quickest way to clone a GregorianCalendar?

问题描述

我试图制作一个对象的深层副本，包括一个 GregorianCalendar 实例。我总是警惕使用 clone（），它似乎没有被覆盖在这里，所以我只是做字段的复制字段。理想情况下，有一个复制构造函数，我可以这样使用：

I'm trying to make a deep copy of an object, including a GregorianCalendar instance. I'm always wary of using clone() and it doesn't seem to have been overridden here, so I'm just doing the copy field by field. Ideally, there'd be a copy constructor, which I could use like so:

GregorianCalendar newCalendar = new GregorianCalendar(oldCalendar);

不幸的是，我在API中找不到任何这样的功能，我需要得到一个确切的副本。所以，要制作这些日历之一的副本，你会怎么做？我在这里缺少一些简单的快捷键？

Unfortunately I can't find any such functionality in the API and am stuck trying to figure out which fields I need to get an exact copy. So, to make a copy of one of these calendars, how would you do it? Am I missing some simple shortcut here?

推荐答案

java.util.Calendar 已覆盖 clone（）这是工作，所以使用它。此外，日历没有深层数据层次结构 - 其数据主要是 int s。

java.util.Calendar has overridden clone() which is working, so use it. Furthermore, Calendar doesn't have deep data hierarchy - its data are mainly ints.

要扩展答案，可以调用 SerializationUtils.clone（..）（从 commons-lang ）对任何对象进行深层复制，如果整个数据层次实现 Serializable

To extend the answer, you can call SerializationUtils.clone(..) (from commons-lang) on any object which makes a deep copy, if the whole data hierarchy implements Serializable

这篇关于克隆GregorianCalendar的最快方法？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！