Phonegap / Cordova 3.4清洁生成得到apple mach-链接器错误 [英] Phonegap/Cordova 3.4 clean build gets apple mach- linker error
本文介绍了Phonegap / Cordova 3.4清洁生成得到apple mach-链接器错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在stackoverflow上尝试了几个选项。但它们都不起作用。
我的项目只是一个干净的phonegap构建。
phonegap从3.3到3.4,我得到这些消息:
https ://www.dropbox.com/s/7zsn21n5sakp0d3/Screenshot%202014-03-18%2012.50.03.png
解决方案 div>
我找到了解决方案:
- 选择您的项目图标
- 。
- 对于架构,请选择$ ARCHS_STANDARD - 标准架构(armv7,armv7s,arm64)
- 选择您的CordovaLib.xcodeproj图标
- 在项目的构建设置(非目标)中,删除条件架构设置
- 对于Architectures,请选择$ ARCHS_STANDARD - 标准架构(armv7,armv7s,arm64) b $ b
- 对于有效的架构,请添加arm64
- Goto 6,
I tried several options on stackoverflow. But none of them seem to work.
My project is just a clean phonegap build.
I just updated phonegap from 3.3 to 3.4 and i get these messages: https://www.dropbox.com/s/7zsn21n5sakp0d3/Screenshot%202014-03-18%2012.50.03.png
解决方案i found the solution:
- Select your Project icon
- Choose Build Settings.
- For "Architectures", select $ARCHS_STANDARD - Standard architectures (armv7, armv7s, arm64)
- For "Valid Architectures", add "arm64"
- Select your CordovaLib.xcodeproj icon
- In the Build Settings for the Project (not Target), delete the conditional architecture settings (this is any value under "Release" or "Debug" - hover to see the minus sign)
- For "Architectures", select $ARCHS_STANDARD - Standard architectures (armv7, armv7s, arm64)
- For "Valid Architectures", add "arm64"
- Goto 6, but now do it for "Target"
这篇关于Phonegap / Cordova 3.4清洁生成得到apple mach-链接器错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文