如何在Scala中将字节数组放入XML [英] How to put a byte array into XML in Scala

问题描述

我正在与.Net Web服务进行交互。根据服务描述，服务器正在等待一个base64Binary类型。

I'm interacting with a .Net web service. According to the service description the server is expecting a base64Binary type.

这是我尝试构建SOAP包的方式：

This is how I'm trying to build the SOAP packet:

  <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
    <soap:Header>
    </soap:Header>
    <soap:Body>
      <uploadFile xmlns="http://localhost/">
        <FileDetails>
          <ReferenceNumber>123</ReferenceNumber>
          <FileName>testfile</FileName>
          <FullFilePath>file</FullFilePath>
          <FileType>1</FileType>
          <FileContents>{request.getContent().array()}</FileContents>
         </FileDetails>
        </uploadFile>
      </soap:Body>
   </soap:Envelope>

在 request.getContent / code>是从PhoneGap中开发的移动应用程序接收的HTTP请求。

In the snippet above the request.getContent().array() is an HTTP request I'm receiving from a mobile application developed in PhoneGap.

服务器响应FileContents无效。任何想法？

The server responds that the FileContents is invalid. Any ideas?

推荐答案

您当前的版本只是写字节（我假设 request.getContent （）.array（）是一个以空格分隔的10进制整数的字节数组：

Your current version is just writing the bytes (I'm assuming request.getContent().array() is an array of bytes) as space-separated base-10 integers:

scala> val bytes = 1 to 10 map(_.toByte) toArray
bytes: Array[Byte] = Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

scala> <FileContents>{bytes}</FileContents>
res0: scala.xml.Elem = <FileContents>1 2 3 4 5 6 7 8 9 10</FileContents>

这绝对不是你想要的。您可以使用像 Apache Commons Codec 这样的库将字节数组编码为字符串（这里我是使用 Base64 code> encoder ）：

This definitely isn't what you want. You can use a library like Apache Commons Codec to encode the byte array as a string (here I'm using the Base64 encoder):

scala> import org.apache.commons.codec.binary.Base64
import org.apache.commons.codec.binary.Base64

scala> <FileContents>{Base64.encodeBase64String(bytes)}</FileContents>
res1: scala.xml.Elem = <FileContents>AQIDBAUGBwgJCg==</FileContents>

你可能需要修改选项，但这更有可能是你需要。

You might have to tinker with the options a bit, but this is much more likely to be what you need.

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