R：计算单个列中连续出现的值 [英] R: count consecutive occurrences of values in a single column

问题描述

我的问题与这个问题非常相似：值的出现的累积顺序< a>

my question is very similar to this one: Cumulative sequence of occurrences of values

但是，如果当前行中的值与上一行不同，我想要重新启动计数。请查看以下输入和预期输出的示例。

But I would like the count of occurrences to 'restart' once the value in the current row is different from the previous row. Please find an example of input and expected output below.

dataset<-data.frame(input = c("a","b","b","a","a","c","a","a","a","a","b","c"))
dataset$expected.output <- c(1,1,2,1,2,1,1,2,3,4,1,1)
dataset

推荐答案

您需要使用 sequence 和 rle ：

> sequence(rle(as.character(dataset$input))$lengths)
 [1] 1 1 2 1 2 1 1 2 3 4 1 1

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