计数div在Jquery中的分页 [英] Counting divs for pagination in Jquery

问题描述

我想在Jquery中创建一个很好的分页。 EG：

I want to create a nice pagination in Jquery for a number of divs I have. EG:

<div class="container">  
    <div id="one">content</div>  
    <div id="two">content</div>  
    <div id="three">content</div>  
    <div id="four">content</div>  
</div> 

数字并不总是相同的，所以我需要计算div，并显示一个分页下面一个。

The number will not always be the same so I need to count the divs, and display a pagination like the one below.

1 | 2 | 3 | 4

点击页码将显示相关的div。我知道如何使用Jquery和css显示和隐藏元素，并且已经弄清楚我可以使用

Clicking on the page number would display the relevant div. I know how to show and hide elements using Jquery and css and have figured out I can count the divs using

var numPages = $（'。容器'）。size（）;

但我无法解决如何显示分页。

but I can't work out how I can display the pagination.

任何指针？

推荐答案

>

Something like this:

// Get all immediate child divs and their count
var $divs = $('div.container > div');
var pages = $divs.length;

// Hide every one but the first
$divs.not(':first').hide();

// Create a container for the pagination
$ul = $('<ul />');

// Create links for pagination inside the ul
for(var i = 0; i < pages; i++) {
    $ul.append($('<li><a href="#" class="pagination" rel="'+i+'">'+i+'</a></li>'));
}

// Insert the pagination container
$('div.container').before($ul);

// Behaviour for clicking the links inside pagination container
$ul.find('a.pagination').click(function() {
    // Get the index from current element's rel attribute
    var index = parseInt($(this).attr('rel'), 10);
    // Hide every div and show the div at the current index's location
    $divs.hide().eq(index).show();
    return false;
});

没有测试，但它应该给你启动器。基本上它只是创建一个ul元素来控制哪些div出现。

Haven't tested that but it should give you starters. Basically it just creates an ul element which controls which divs show up.

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